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3 years ago

5

Javier and 2 of his friends, James and Alex, are planning on taking a trip to Miami, FL. They plan on driving and would like to

rent a car. They have a choice of two rental cars, each coming with a full tank of gas. The compact car has a 16 gallon tank and averages 25 miles per gallon. The midsize car has a 21 gallon tank and averages 20 miles per gallon.

1 answer:

NeX [460]3 years ago

5 0

The compact car has a range of 400 miles because 16x25. On the other hand the sedan has a range of 420 miles because of 21x20. Therefore they should get the sedan because it can travel farther.

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$87.00 divided by 5 can u divide pls

Illusion [34]

$87.00/5 is $17.4 dollars

6 0

4 years ago

When the sum of the internal angles of a polygon is 10 right angles, then how many sides does it have?

Varvara68 [4.7K]

Answer:

7

Step-by-step explanation:

Let's say our sum is s.

s = 10 right angles

a right angle is 90 degrees

s = 10 (90)

s= 900

Given the amount of sides in a polygon (n), the sum of the interior angles is equal to

(n-2) * 180

Therefore, the sum of the interior angles is equal to

(n-2) * 180 = 900

divide both sides by 180 to help isolate n

n-2 = 5

add 2 to both sides to isolate n

n = 7

3 0

3 years ago

Using the distributive property, which number sentence represents the total area of the rectangle?

Daniel [21]

D. is the answer. Your welcome

8 0

3 years ago

Does 6(2x-6)=-7(-2x+4) have no solution or infinite solution

tatiyna

Answer:

It does not.

Step-by-step explanation:

$6(2x - 6) = -7(-2x + 4); \\ 6 * 2x - 6 * 6 = -7 * (-2x) + (-7) * 4; \\ 12x - 36 = 14x - 28; \\ 14x - 12x = -36 + 28; \\ 2x = -8; \\ x = -4.$

$\{-4\}$ is our set of solutions. Answering your question, it does not.

5 0

2 years ago

Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. Sketch the re

alukav5142 [94]

Answer:

Step-by-step explanation:

$\text{Given that:}$

$y = 1+ sec(x) \ \ y =3$

$\text{we draw the graph and the curves intersect at:}$

$x = - \dfrac{\pi}{3} \ and \ x = \dfrac{\pi}{3}$

$\text{Applying washer method;}$

$f(x) _{outer} - g(x) _{inner} --- (1)$

$V= \int ^b_a A(x) \ dx --- (2)$

$\text{outer radius = 3 - 1 = 2}$

$\text{inner radius =}$ $( 1 + sec(x) ) - 1 = sec (x)$

$A(x) = \pi ((2)^2 -(sec(x)^2) \\ \\ A(x) = \pi (4 - sec^2 (x)) ---- (3)$

$\text{The volume V =}\int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ A(x) \ dx$

$V = \int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ \pi (4- sec^2 (x) ) \ dx$

$V = 2 \pi \int ^{\dfrac{\pi}{3}}_{0}( 4 - sec^2 (x)) \ dx$

$V = 2 \pi \int ^{\pi/3}_{0} 4 . \ dx - 2 \pi \int ^{\pi/3}_{0} sec^2 (x) \ dx$

$V = 2 \pi(4) \int ^{\pi/3}_{0} 1 . \ dx - 2 \pi \Big( tan (x)\Big )^{\dfrac{\pi}{3}}_{0}$

$V = 8 \pi(x)^{\dfrac{\pi}{3}}_{0} - 2 \pi \Big( tan \dfrac{\pi}{3} -tan (0)\Big )$

$V = 8 \pi({\dfrac{\pi}{3}}-{0}) - 2 \pi \Big( tan \sqrt{3}-(0)\Big )$

$V = 8 \pi({\dfrac{\pi}{3}}) - 2 \pi \Big( \sqrt{3}\Big )$

$\mathbf{V = 2 \pi \Big(\dfrac{4\pi}{3}- \sqrt{3} \Big)}$

8 0

3 years ago