This is the answer to the problem. You basically substitute the -6 in for the f(x)
Answer:
500-25w
200
Step-by-step explanation:
Answer:
It doesn't matter that much
Step-by-step explanation:
I know it from last year
Answer:
The minimum score required for an A grade is 83.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 72.3 and a standard deviation of 8.
This means that 
Find the minimum score required for an A grade.
This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.




The minimum score required for an A grade is 83.
Answer:
Step-by-step explanation:
Interest earned during the rest of 2 years and 6 months
40 + 40 + 40 = 120
he will be getting 1000 at the time of maturity ie after 2.5 years .
Total receipt = 1000 + 120 = 1120
investment made = 820
total receipt earned = 1120
profit made = 300
time = 2.5 years
profit = investment x rate of intt x time / 100
300 = 820 x r x 2.5 / 100 where r is rate of interest
r = 30000 / 820 x 2.5
= 14.63 % .