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3 years ago

7

Jake owes $3,400 on his credit card. he is not charging any additional purchases because he wants to get this debt paid in full.

the card has an apr of 13.9 percent. how much longer will it take him to pay off this balance if he makes monthly payments of $50 rather than $60?

1 answer:

adell [148]3 years ago

6 0

The answer is 68 times

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Marina86 [1]

Answer:

2/66 is ur answer

Step-by-step explanation:

because it will give u ur answer

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2 years ago

What is the rule of function? (0,0),(1,4),(2,16),(3,36)

lilavasa [31]

When the first number increases by one the second number is added by 4's. So from the first part to the second it added 4 then from the 2nd to the 3rd it skips adding 8 to then just add 12. Then from the 3rd to the 4th it skips adding 16 and adds 20. So the next set of numbers would be (4,64) because it skips adding the 24 and adds the 28.
Hope this helps and is not to confusing :)

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3 years ago

What is the value of r

mezya [45]

Answer:The value of R at atm that is at standard atmospheric pressure is R = 8.3144598 J. mol-1. K-1.

Step-by-step explanation:i got this from someone

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3 years ago

Can someone please help with this ?

olga nikolaevna [1]

Answer:1/32

Step-by-step explanation:

8 0

3 years ago

In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 15 boys an

denis-greek [22]

Answer:

There are a total of possible 1820 results.

Step-by-step explanation:

Since there are two competitions, one for boys and one for girls, and we want all the possible results we will calculate the possible combinations for the boys and multiply them by the possible combinations for the girls. This is shown below:

$Boys = \frac{15!}{3!(15 - 3)!} = \frac{15!}{3!12!} = \frac{15*14*13*12!}{3!12!}\\Boys = \frac{15*14*13}{3*2*1}\\Boys = \frac{15*14*13}{3*2*1}\\Boys = 455$

$Girls = \frac{4!}{3!*(4 - 3)!}\\Girls = \frac{4*3!}{3!}\\Girls = 4$

Total number of possible results:

$results = 4*455\\results = 1820$

3 0

3 years ago