(x^1/8 y^1/4 z^1/2)^8
(8 √x 4 √y √z^8)
(8 √x 8 √y^2 8 √z^4)^8
8 √xy^2z^4^8
Solution: xy^2 z^4
<h3>Answer :- </h3>
- Let the three consecutive numbers be x -2 , x and x + 2
- Their sum = ( x - 2 ) + ( x + 2 ) = 3x
- This is the given equal to 54
- 3x = 54 or x = 54/3
- x = 18
<em>Thus </em><em>,</em><em> </em><em>the </em><em>required </em><em>numbers </em><em>are </em><em>1</em><em>6</em><em> </em><em>,</em><em> </em><em>1</em><em>8</em><em> </em><em>,</em><em> </em><em>2</em><em>0</em><em> </em>
Answer:
5.
2.4 = E
-1 4/5 = B
-0.2 =C
-2 3/5 = A
0.6 = D
6. one line under -1
Step-by-step explanation:
5. On the number line each short line is by 2 so basically 2 + 2 + 2
6. -4/3 = 1/1/3 (simplify)
Ok, so after you do -8a+5a, you also have to do 6 -35, getting the equation
-29-3a
