Answer:
prolly say 5 ............
2x + 3y = 3 y = 8 – 3x
we have 2 equations
first equations: <span>2x + 3y = 3 y
</span>the second equation: 3y = 8 – 3x => <span>8-3x=3y
</span><span>------------------------------------------------------------
2x+3y=3y</span>2x=3y-3y
2x=0
x=0
8-3x=3y
8-0=3y
8=3y
y=8/3
S={x=0 ; y=8/3 }
Answer:
54
Step-by-step explanation:
Answer:
2x² + 3x + 4 + (17x + 9) / (x² − 4)
Step-by-step explanation:
Start by setting up the division. Make sure to write all the coefficients, even the zero ones.
x² + 0x − 4 | 2x⁴ + 3x³ − 4x² + 5x − 7
Start by dividing the first term of the dividend (2x⁴) by the first term of the divisor (x²). That's 2x²; it'll be the first term in quotient. Multiply the divisor by 2x²:
2x⁴ + 0x³ − 8x²
Subtract that from the first three terms of the dividend:
3x³ + 4x²
Drop down the next term from the dividend, and start the process all over again.
3x³ + 4x² + 5x
When you finish, the quotient will be 2x² + 3x + 4, and the remainder will be 17x + 9.
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