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Westkost [7]
2 years ago
14

) Identify each graph as a linear function, nonlinear function, or not a function.

Mathematics
2 answers:
vredina [299]2 years ago
8 0

Answer:

See below.

Step-by-step explanation:

Not a function

Function

Nonlinear function

Not a function

-hope it helps

suter [353]2 years ago
4 0

Answer:

1.Non linear function

2. Linear function

3. Non linear function

4. Not a Function

Step-by-step explanation:

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Solve the inequality: -2x>-6
DedPeter [7]

Answer:

x < 3

Step-by-step explanation:

Divide both sides by -2

x < -6/-2

Two negatives equals a positive

x < 6/2

Simplify 6/2 to 3

x < 3

Hope this helps!

-Jerc

7 0
3 years ago
A sparkling-water distributor wants to make up 200 gallons of sparkling water to sell for $5.00 per gallon. She wishes to mix th
Sedbober [7]
Assuming she make no profit and no loss from the business.

Let the number of gallons of the $8 grade water used be x, that of the $3 grade water, y, and that of the $4.50 grade water be z, then:

x + y + z = 200 . . . (1)
8x + 3y + 4.5z = 200(5) = 1,000 . . . (2)
z = 2y . . . (3)

Putting equation (3) into equations (1) and (2), we have:

x + y + 2y = 200
or x + 3y = 200 . . . (4)
and
8x + 3y + 4.5(2y) = 1000
or 8x + 3y + 9y = 1000
or 8x + 12y = 1000 . . . (5)

Multiplying equation (4) by 4, we have:
4x + 12y = 800 . . . (6)

Subtracting equation (6) from equation (5), we have:
4x = 200
or x = 200 / 4 = 50

Substituting for x into equation (4), we have:
50 + 3y = 200
or 3y = 200 - 50 = 150
or y = 150 / 3 = 50

Substituting for z into equation (3) gives:

z = 2(50) = 100

Therefore, 50 gallons each of the $8 grade water and the $3 grade water should be used and 100 gallons of the $4.50 grade water.
4 0
3 years ago
I dont get this it's geometry.
SIZIF [17.4K]
Angle 2 is half of 115 so it would be 57.5 and angle 1 would be 122.5 degrees
6 0
3 years ago
This is so confusing, pls help!!
liq [111]

Answer:

2 1/4 cubic units is the answer

3 0
3 years ago
FORM A CUBIC POLYNOMIAL WHOSE ZEROS ARE -3,-1 AND 2
Firdavs [7]

(x+3)(x+1)(x-2)=\\(x^2+x+3x+3)(x-2)=\\(x^2+4x+3)(x-2)=\\x^3-2x^2+4x^2-8x+3x-6=\\x^3+2x^2-5x-6

7 0
3 years ago
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