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oksano4ka [1.4K]
3 years ago
12

Ramon says that he needs the same amount

Mathematics
2 answers:
WINSTONCH [101]3 years ago
8 0
If Ramon needs the same amount of x as someone else find the missing part in the problem then the amount Ramon need (x) is you answer.

murzikaleks [220]3 years ago
4 0
This could be fit for a picture!!
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1)Sheyna drive to the lake and back. It took two hours less time to get there than it did to get back. The average speed on the
ipn [44]

Answer:

8 hours

Step-by-step explanation:

Given:

Sheyna drives to the lake with average speed of 60 mph and

v_1 = 60\ mph

Sheyna drives back from the lake with average speed of 36 mph

v_2 = 36\ mph

It took 2 hours less time to get there than it did to get back.

Let t_1 be the time taken to drive to lake.

Let t_2 be the time taken to drive back from lake.

t_2-t_1 = 2 hrs ..... (1)

To find:

Total time taken = ?

t_1+t_2 = ?

Solution:

Let D be the distance to lake.

Formula for time is given as:

Time =\dfrac{Distance}{Speed }

t_1 = \dfrac{D}{60}\ hrs

t_2 = \dfrac{D}{36}\ hrs

Putting in equation (1):

\dfrac{D}{36}-\dfrac{D}{60} = 2\\\Rightarrow \dfrac{5D-3D}{180} = 2\\\Rightarrow \dfrac{2D}{180} = 2\\\Rightarrow D = 180\ miles

So,

t_1 = \dfrac{180}{60}\ hrs = 3 \ hrs

t_2 = \dfrac{180}{36}\ hrs = 5\ hrs

So, the answer is:

t_1+t_2 = \bold{8\ hrs}

8 0
3 years ago
a wall is 2m at one end and 2.4m at the other end. the area of the wall is 26.4m squared. what is the length of the wall?
andrew11 [14]
Since the height is different on both ends, we can assume that the wall is a trapezoid. Knowing that, we can replace the measures we know in the formula and our onky variable is the length of the wall - we only need to isolate it. A= ((b+B)h)/2 26.4=((2+2.4)h)/2 52.8=4.4h h=12
6 0
3 years ago
The probability of passing the math class of Professor Jones is 64%, the probability of passing Professor Smith's physics class
alexgriva [62]

Answer:

The probability of using one or the other is 36%

Step-by-step explanation:

For solving this problem it is easy if we see it in a ven diagram, for this first we are going to name the initial conditions with some variables:

Probability of passing Professor Jones math class = 64% =0,64

P(J) = 0.64

Probabiliry of passing Professor Smith's physics class = 32% =0.32

P(S) = 0.32

Probability of passing both is = 30% = 0.30

P(JnS) = 0.30 (Is is an intersection so it is in the middle of the ven diagram

We need to know which is the probability of pasing one or the other for this we need to take out the probability of passing both for this we have to add the probability of passing  Professor Jones math class with the probabiliry of passing Professor Smith's physics class and substract the probability of passing both for each one:

P(JuS) = (P(J) - P(JnS)) + (P(S) - P(JnS)) = (0.64 - 0.30) + (0.32 - 0.30) = 0.34 + 0.02 = 0.36 = 36%

If you check the ven diagram you can see that if we add all what is in red we will have the probability of passing Professor Jones math class and if we add all what is in blue we wiill have the probability of passing Professor Smith's physics class, and if we add just what is in each corner we will get the same value that is the probabilty of passsing one or the other.

5 0
3 years ago
The following items are in the shape of a square. How many squares are
kramer
A because I have done this before
7 0
3 years ago
Read 2 more answers
There are three blue marvels and five red marvels in a bag you randomly select a marble and put it it back in the back if you do
olga nikolaevna [1]

Answer:

25 times

Explanation:

Blue Marvels: 3

Red Marvels: 5

Total Marvels: 5 + 3 = 8 marvels

Probability: favorable outcomes/total outcomes

Probability - red marble =  5/8

After Doing 40 times:

= 5/8 × 40

= 25

7 0
2 years ago
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