Find the area of the shaded segment of the circle.

ABCD is a parallelogram. If m

labwork [276]

Um please continue the question, thanks!

7 0

3 years ago

TELE

Aleonysh [2.5K]

Answer:

$23271.49

Step-by-step explanation:

The function $C(t) = C(1 + r)^{t}$ models the rise in the cost of a product that has a cost of C today, subject to an average yearly inflation rate of r for t years.

Now, if the average annual rate of inflation over the next 8 years is assumed to be 2.5% then we have to find the inflation-adjusted cost of a $19100 motorcycle after 8 years.

Therefore, the cost will be $C(8) = 19100(1 + \frac{2.5}{100} )^{8} = 23271.49$ dollars. (Answer)

8 0

3 years ago

1. A given binomial distribution has a mean of 153.1 and a standard deviation of 18.2. Would a value of 187 be considered usual

Triss [41]

Answer:

Usual, because the result is between the minimum and maximum usual values.

Step-by-step explanation:

To identify if the value is usual or unusual we're going to use the Range rule of thumbs which states that most values should lie within 2 standard deviations of the mean. If the value lies outside those limits, we can tell that it's an unusual value.

Therefore:

Maximum usual value: μ + 2σ

Minimum usual value: μ - 2σ

In this case:

μ = 153.1

σ = 18.2

Therefore:

Maximum usual value: 189.5

Minimum usual value: 116.7

Therefore, the value of 187 lies within the limits. Therefore, the correct option is D. Usual, because the result is between the minimum and maximum usual values.

8 0

3 years ago

When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let

sergiy2304 [10]

Answer:

(a) P(X=3) = 0.093

(b) P(X≤3) = 0.966

(c) P(X≥4) = 0.034

(d) P(1≤X≤3) = 0.688

(e) The probability that none of the 25 boards is defective is 0.277.

(f) The expected value and standard deviation of X is 1.25 and 1.089 respectively.

Step-by-step explanation:

We are given that when circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%.

Let X = the number of defective boards in a random sample of size, n = 25

So, X ∼ Bin(25,0.05)

The probability distribution for the binomial distribution is given by;

$P(X=r)= \binom{n}{r} \times p^{r}\times (1-p)^{n-r} ; x = 0,1,2,......$

where, n = number of trials (samples) taken = 25

r = number of success

p = probability of success which in our question is percentage

of defectivs, i.e. 5%

(a) P(X = 3) = $\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $2300 \times 0.05^{3}\times 0.95^{22}$

= 0.093

(b) P(X $\leq$ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{0} \times 0.05^{0}\times (1-0.05)^{25-0}+\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $1 \times 1 \times 0.95^{25}+25 \times 0.05^{1}\times 0.95^{24}+300 \times 0.05^{2}\times 0.95^{23}+2300 \times 0.05^{3}\times 0.95^{22}$

= 0.966

(c) P(X $\geq$ 4) = 1 - P(X < 4) = 1 - P(X $\leq$ 3)

= 1 - 0.966

= 0.034

(d) P(1 ≤ X ≤ 3) = P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$