The integral is path-independent if we can find a scalar function <em>f</em> such that grad(<em>f</em> ) = <em>A</em>. This requires
Take the first PDE and integrate both sides with respect to <em>x</em> to get
where <em>g</em> is assumed to be a function of <em>y</em> alone. Differentiating this with respect to <em>x</em> gives
which would mean <em>g</em> is *not* a function of only <em>y</em>, but also <em>x</em>, contradicting our assumption. So the integral is path-dependent.
Parameterize the unit circle (call it <em>C</em>) by the vector function,
with <em>t</em> between 0 and 2π.
Note that this parameterization takes <em>C</em> to have counter-clockwise orientation; if we compute the line integral of <em>A</em> over <em>C</em>, we can multiply the result by -1 to get the value of the integral in the opposite, clockwise direction.
Then
and the (counter-clockwise) integral over <em>C</em> is
and so the integral in the direction we want is -2π.
By the way, that the integral doesn't have a value of 0 is more evidence of the fact that the integral is path-dependent.
Answer: the probability it will come up heads 25 or fewer times is 0.019
Step-by-step explanation:
Given that;
n = 50
p = 0.65
so, q = 1 - p = 0.35
np = 50 × 0.65 = 32.5 ≥ 10
nq = 50 × 0.35 = 17.5 ≥ 10
so, we need to use Normal Approximation for the Binomial Distribution
μ = np = 50 × 0.65 = 32.5
σ = √(npq) = √( 50 × 0.65 × 0.35 ) = 3.3726
now, the probability that it will come up heads 25 or few times will be;
⇒ P( x≤25)
{using continuity correction}
⇒ P[ z < (25.5 - 32.5)/3.3726 ]
⇒ P[ z < -2.0755 ]
using z-table
= 0.01923 ≈ 0.019 { 3 decimal places}
Therefore the probability it will come up heads 25 or fewer times is 0.019
Answer:
Option a is correct.
The rotation for the transformation to △A'B'C' is , rotation of 90 degree.
Explanation:
In △ABC
The coordinate of point A = (1,1) , B = (3,1) and C = (1,4).
Rotate triangle ABC 90 degree's around the origin;
The rule for this transformation is:- (x,y) to (-y ,x)
A(1,1) to A' (-1,1) ,
B(3,1) to B'(-1 , 3) and
C(1,4) to C' (-4,1)
therefore, rotation of 90 degree counter clockwise rotation around the origin results in the transformation of △ABC to △A'B'C'
Answer:7
Step-by-step explanation:
Answer:
22.9 yards
Step-by-step explanation:
Since b² = a² - c² where a = vertex of major axis, 2a = 50 yards the length of the major axis. So , a = 50/2 = 25 yards. c = focus of chamber = 10 yards from center and b = vertex of minor axis.
So, b = ±√(a² - c²)
= ±√(25² - 10²)
= ±√(625 - 100)
= ±√525
= ±22.91 yards
≅ ± 22.9 yards
Since b = length of minor axis from center of chamber = 22.91 yards. So, he should build the whisper chamber 22.9 yards out from the center of the chamber.