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V125BC [204]
3 years ago
10

Robert has 60 feet of fence to make a dog pen. He will use the house for one side of the pen, as shown above. What dimensions wi

ll make the largest pen?
A.
10 ft by 40 ft
B.
12 ft by 36 ft
C.
15 ft by 30 ft
D.
20 ft by 20 ft
Mathematics
1 answer:
irinina [24]3 years ago
7 0

The formula for an area of a regular parallelogram is:

A = l * w

Where,

l = length

w = width

We are given that the total measurement of fence is only 60 feet and one side of the house is used as one side of the pen. Therefore,

l + 2 w = 60

<span>or simplifying to make an explicit expression for one  variable, say l:</span>

l = 60 – 2 w

<span>Substituting to the 1st equation:</span>

A = (60 – 2 w) * w

A = 60 w – 2 w^2

<span>The maxima are obtained by getting the 1st derivative then equating dA/dw = 0:</span>

dA/dw = 60 – 4 w

60 – 4 w = 0

4 w = 60

w = 15

Since l = 60 - 2w

l = 60 – 30

l = 30

<span>Therefore the dimension that will make the largest pen is 15 ft by 30 ft.</span>

<span>ANSWER: C</span>

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Can someone please help me with this
Mama L [17]

Answer:

27.

<em>Equation of 2 tangent lines at the given curve going through point P is:</em>

<em>y = -7x + 1</em>

<em>y = x + 1</em>

28.

<u>Part 1:</u>  400 feet

<u>Part 2:</u>  Velocity is +96 feet/second (or 96 feet/second UPWARD)  & Speed is 96 feet per second

<u>Part 3:</u>  acceleration at any time t is -32 feet/second squared

<u>Part 4:</u>  t = 10 seconds

29.

<u>Part 1:</u>  Average Rate of Change = -15

<u>Part 2:</u>  The instantaneous rate of change at x = 2 is -8  &  at x = 3 is -23

<u />

Step-by-step explanation:

27.

First of all, the equation of tangent line is given by:

y-y_1=m(x-x_1)

Where m is the slope, or the derivative of the function

Now,

If we take a point x, the corresponding y point would be x^2-3x+5, so the point would be  (x,x^2-3x+5)

Also, the derivative is:

f(x)=x^2-3x+5\\f'(x)=2x-3

Hence, we can equate the DERIVATIVE (slope) and the slope expression through the point given (0,1) and the point we found (x,x^2-3x+5)

The slope is  \frac{y_2-y_1}{x_2-x_1}

So we have:

\frac{x^2-3x+5-1}{x-0}\\=\frac{x^2-3x+4}{x}

Now, we equate:

2x-3=\frac{x^2-3x+4}{x}

We need to solve this for x. Shown below:

2x-3=\frac{x^2-3x+4}{x}\\x(2x-3)=x^2-3x+4\\2x^2-3x=x^2-3x+4\\x^2=4\\x=-2,2

So, this is the x values of the point of tangency. We evaluate the derivative at these 2 points, respectively.

f'(x)=2x-3\\f'(-2)=2(-2)-3=-7\\f'(2)=2(2)-3=1

Now, we find 2 equations of tangent lines through the point (0,1) and with respective slopes of -7 and 1. Shown below:

y-y_1=m(x-x_1)\\y-1=-7(x-0)\\y-1=-7x\\y=-7x+1

and

y-y_1=m(x-x_1)\\y-1=1(x-0)\\y-1=x\\y=x+1

<em>So equation of 2 tangent lines at the given curve going through point P is:</em>

<em>y = -7x + 1</em>

<em>y = x + 1</em>

<em></em>

28.

<u>Part 1:</u>

The highest point is basically the maximum value of the position function. To get maximum, we differentiate and set it equal to 0. Let's do this:

s(t)=160t-16t^2\\s'(t)=160-32t\\s'(t)=0\\160-32t=0\\32t=160\\t=\frac{160}{32}\\t=5

So, at t = 5, it reaches max height. We plug in t = 5 into position equation to find max height:

s(t)=160t-16t^2\\s(5)=160(5)-16(5^2)\\=400

max height = 400 feet

<u>Part 2:</u>

Velocity is speed, but with direction.

We also know the position function differentiated, is the velocity function.

Let's first find time(s) when position is at 256 feet. So we set position function to 256 and find t:

s(t)=160t-16t^2\\256=160t-16t^2\\16t^2-160t+256=0\\t^2-10t+16=0\\(t-2)(t-8)=0\\t=2,8

At t = 2, the velocity is:

s'(t)=v(t)=160-32t\\v(2)=160-32(2)\\v(2)=96

It is going UPWARD at this point, so the velocity is +96 feet/second or 96 feet/second going UPWARD

The corresponding speed (without +, -, direction) is simply 96 feet/second

<u>Part 3:</u>

We know the acceleration is the differentiation of the velocity function. let's find it:

v(t)=160-32t\\v'(t)=a(t)=-32

hence, the acceleration at any time t is -32 feet/second squared

<u>Part 4:</u>

The rock hits the ground when the position is 0 (at ground). So we equate the position function, s(t), to 0 and find time when it hits the ground. Shown below:

s(t)=160t-16t^2\\0=160t-16t^2\\16t^2-160t=0\\16t(t-10)=0\\t=0,10

We disregard t = 0 because that's basically starting. So we take t = 10 seconds as our answer and we know rock hits the ground at t = 10 seconds.

29.

<u>Part 1:</u>

The average rate of change is basically the slope, which is

Slope = Change in y/ Change in x

The x values are given, from 2 to 3, and we need to find corresponding y values by plugging in the x values in the function. So,

When x = 2,  y=f(2)=-(2)^3 + 4(2) + 2=2

When x = 3,  y=f(3)=-(3)^3 + 4(3) + 2=-13

Hence,

Average Rate of Change = \frac{-13-2}{3-2}=-15

<u>Part 2:</u>

The instantaneous rate of change is got by differentiating the function and plugging the 2 points and finding the difference.

First, let's differentiate:

f(x)=-x^3+4x+2\\f'(x)=-3x^2+4

Now, find the derivative at 3,

f'(x)=-3x^2+4\\f'(3)=-3(3)^2+4=-23

finding derivative at 2,

f'(x)=-3x^2+4\\f'(2)=-3(2)^2+4=-8

The instantaneous rate of change at x = 2 is -8  &  at x = 3 is -23

6 0
3 years ago
The cost to produce a product is modeled by the function f(x) = 5x2 − 70x 258, where x is the number of products produced. compl
ad-work [718]

The minimum cost to produce the product is $7.

What are functions?

  • A function from a set X to a set Y allocates exactly one element of Y to each element of X.

To determine the minimum cost:

We have to determine the minimum cost of producing this product.

Since f(x) = 5x^{2} -70x+258.

Now, consider the equation 5x^{2} -70x+258= 0.

Dividing the above equation by 5, we get

x^{2} -70x/5+258/5=0\\x^{2} -14x+258/5=0

Now, considering the coefficient of 'x', dividing it by '2' and then adding and subtracting the square of the number which we got after dividing.

Since the coefficient of 'x' is 14, and half of 14 is '7'.

So, adding and subtracting from the above equation.

x^{2} -14x+(7)^{2} -(7)^{2}+258/5=0\\x^{2} -14x+49 -49+258/5=0\\(x-7)^{2} -49+258/5=0\\(x-7)^{2} +258-245/5=0\\(x-7)^{2} +13/5=0\\5(x-7)^{2} +13=0

Now, we have to determine the minimum cost to produce the product.

Since f(x) = 5x^{2} -70x+258.

f'(x) = 10x-70

Now, let f'(x)=0

10x-70=0\\10x=70

Therefore, x=7

Now, consider which is greater than 0.

Therefore, x= 7 is the minimum cost.

Know more about functions here:

brainly.com/question/25638609

#SPJ4

5 0
2 years ago
Determine if the situation is additive or multiplicative AND determine the equation that corresponds to the situation.
diamong [38]

Answer:

The situation is Multiplicative.

The equation will be y=2x

Step-by-step explanation:

We are given the table:

Input (x)          5       8      11

Output (y)      10     16     22

Looking at the table, we see that the value of x is doubled to get value of y

Looking at the trend: 5(2) = 10

8(2) = 16

11(2) = 22

The value of x is multiplies by 2 to get value of y.

So, The situation is Multiplicative.

Now, The equation will be y=2x

because we saw the trend, that every value of x is multiplied by 2 to get value of y.

3 0
3 years ago
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Karen has $0.90 in dimes, d, and nickels, n. She has
kumpel [21]
Why does Karen need to know this. Karen is supposed to be at the managers office!
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3 years ago
The probability that someone owns an iPhone is 62%. The probability that someone owns an Apple watch is 15%. The probability som
Dmitry [639]
ANSWER

The probability that someone owns an iPhone or an Apple watch is

P(I \cup \: A) = 69\%

or

P(I \cup \: A) = 0.69


EXPLANATION

We were given that, the probability that someone owns an iPhone is

P(I)=62\%

and the probability that someone owns Apple watch is

P(A)=15\%


and the probability that someone owns both is


P(I \cap \: A) = 8\%
Since the intersection is not zero, it means the two events are not mutually exclusive.

The probability that someone owns an iPhone or Apple phone is

P(I \cup \: A) = P(I) + P(A) - P(I  \cap \: A)


We substitute the values to get,


P(I \cup \: A) = 62\% + 15\% - 8\%

P(I \cup \: A) = 69\%

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3 years ago
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