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Firdavs [7]
3 years ago
13

*in the image above x=23 cm. find the surface area of the figure (help pls)

Mathematics
1 answer:
svlad2 [7]3 years ago
8 0

Answer:

3174cm^{2}

Step-by-step explanation:

Each square has an area of 529cm^{2}

So we multiply that by the number of squares which is 6.

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etty sets up a lemonade stand and charges $1 per glass. It cost her $50 to set up the stand. Which function gives the profit, p,
gizmo_the_mogwai [7]
If you would like to find the function that gives the profit Betty makes by selling a number of glasses of lemonade, you can find this using the following steps:
p ... profitg ... glasses of lemonade
f(g) = p = g * $1 - $50
The correct result would be f(g) = g * $1 - $50.
credit to Neuron, <span>Ambitious
verified answer from him
brainly.com/question/1638432
</span>
4 0
4 years ago
A group of students must collect at least $150 to organize a science fair. They have already collected $30. Which graph best rep
Mama L [17]
The answer is

A. Number line graph with closed circle on 120 and shading to the right.

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7 0
3 years ago
I need help please ASAP i will mark branlist
gavmur [86]
It's B!------------------------------
5 0
3 years ago
Addison worked 11 more hours this week than last week. In total, she worked 65 hours this week and last week. Using the equation
Anestetic [448]

Answer:

27 hours

Step-by-step explanation:

Just do the reverse. 65-11 = 54. 54 / 2 = 27.

5 0
3 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3&#10;

has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
Read 2 more answers
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