Answer:
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Step-by-step explanation:
We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 16 - 1 = 15
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.9467
The margin of error is:
M = T*s = 2.9467*0.058 = 0.171
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg
The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Answer:
1/3
Step-by-step explanation:
The formula for computing the sum of an infinite geometric series is
where r is between -1 and 1 and
is the common ratio, and
is the first term of the series.
So let's plug in:


I multiplied bottom and top by 10.
I divided top and bottom by 3.
The sum is 1/3.
7 ft. i believe, if not... its 6 ft i don't know if this helps, but if it does, your wecome
Answer:
2/3
1
3/2
Step-by-step explanation:



The appropriate choice is z = 1.41.
The empirical rule tells you 68% of the distribution is within 1 standard deviation, so p(z > 1) ≈ 0.17. This means the z value is more than 1 for the probability to drop to 0.08. The only choice that is greater than 1 is 1.41. (The number is actually about 1.40507.)