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Harman [31]
3 years ago
15

Find the sum of this infinite geometric series where a1=0.3 and r=0.1

Mathematics
1 answer:
ratelena [41]3 years ago
8 0

Answer:

1/3

Step-by-step explanation:

The formula for computing the sum of an infinite geometric series is

S=\frac{a_1}{1-r} where r is between -1 and 1 and r is the common ratio, and a_1 is the first term of the series.

So let's plug in:

S=\frac{0.3}{1-0.1}

S=\frac{0.3}{0.9}

S=\frac{3}{9} I multiplied bottom and top by 10.

S=\frac{1}{3} I divided top and bottom by 3.

The sum is 1/3.

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What is15 qt/h= gal min
Brilliant_brown [7]

we have

15 \frac{qt}{h}

we know that

1 quarter is equal to 0.25 gallon

1 hour is equal to 60 minutes

convert \frac{qt}{h} to \frac{gal}{min}

15 \frac{qt}{h} =15* \frac{0.25}{60} = 0.0625\frac{gal}{min}

therefore

the answer is

0.0625\frac{gal}{min}

5 0
3 years ago
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8. The endpoints of GH are G(-8, -9) and H(8,3). Find the coordinates of the midpoint M
Ad libitum [116K]

Answer:SEE BELOW

Step-by-step explanation:

Average the X and Y coordinates (X,Y)

X = (-8 + 8)/2 = 0

Y = (-9 + 3)/2 = -3

(X,Y) = (0,-3)

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3 years ago
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Example Given
Delicious77 [7]
The answer is 5

a^2+b^2=c^2
9+16=25
sq root of 25 is 5
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3 years ago
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Perform the computation and write the result in scientific notation:
gtnhenbr [62]

Answer:

6.06 x 10^{9}

Step-by-step explanation:

(5.25 x 10^{5} ) / (8.7 x 10^{-5} )

= (5.25 x 10^{5} ) x( 10^{5} )/ (8.7 )

= (5.25 x 10^{5 + 5} )/ (8.7 )

= 0.606 x 10^{10}

= 6.06 x 10^{9}

6 0
3 years ago
A pyramid of logs has 2 logs in the top row, 4 logs in the second row from the top, 6 logs in the third row from the top, and so
mamaluj [8]

Answer:

1) Is the pattern an arithmetic sequence?​

Yes it is

2)Identify a and d.​

a = First term = 2

d = Common difference = 2

3) Write the 50th term of the sequence.​

50th term = 100

4) Find the total number of logs in the first 10 rows.​

= 1010 logs

Step-by-step explanation:

Is the pattern an arithmetic sequence?​

Yes it is

2) Identify a and d.​

A pyramid of logs has 2 logs in the top row, 4 logs in the second row from the top, 6 logs in the third row from the top, and so on,

The formula for arithmetic sequence =

an = a+ (n - 1)d

a = First term

d = Common difference

For the above question:

a = 2

d = Second term - First term

= 4 - 2

d = 2

3) Write the 50th term of the sequence.​

Using the formula for arithmetic sequence

an = a+ (n - 1)d

a = 2

n = 50

d = 2

a50 = 2 + (50 - 1)2

= 2 + (49)2

= 2 + 98

= 100

The 50th term = 100

4)Find the total number of logs in the first 10 rows.​

Sum of first n terms = n/2(a + l)

n = 10

a = first term = 2

We are told that there are 200 logs in the bottom row, hence:

l = last term = 200 logs

Hence,

Sn = 10/2×[ (2 + 200

= 5(202)

= 1010 logs

7 0
3 years ago
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