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tatiyna
3 years ago
12

What is the approximate circumference of a circle with a diameter of 500 kilometers ? use pi= 3.14.

Mathematics
1 answer:
alexira [117]3 years ago
7 0
The formula for a circumference is L=pi*diameter
So you have to replace d for 500:
L=circumference= 3.14*500 = 1570 kilometers, so answer is "b" 
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Chapter : EXPONENTS AND POWERS<br> Can anyone give me answer for this please
Aneli [31]

The value of given expression is: 3

<h3>What is exponents and powers?</h3>

Exponent refers to the number of times a number is used in a multiplication. Power can be defined as a number being multiplied by itself a specific number of times.

9*(15)³/45 * 5^{-2}/9

= 3²* 3³*5³/5² * 3² * 3² * 5

= 3^{2+3-4} * 5^{3-3}

= 3*1

=3

Learn more about exponents and power here:

brainly.com/question/15722035

#SPJ1

5 0
2 years ago
Determine if the two figures are congruent and explain your answer using transformations.
IRISSAK [1]

Answer:

Comparing each pair of lines,

AB and EF,

BC and FG,

CD and GH,

DA and HE.

For, AB and EF,

If we take a look at both the lines they are the mirror image of each other, the distance between point A and B is 1 unit upwards, and 2 unit sidewise, similarly between point E and F the distance is 1 unit upwards, and 2 unit sidewise. therefore, the length of both the lines is the same.

Also, we can use the formula, for the distance between two points on a coordinate plane,

,

As we can see in the image,

A = (-1, 1),

B = (-3, 2),

C = (-4, 4),

D = (-2, 6),

E = (2, 0),

F = (4, 1),

G = (5, 3),

H = (3, 5),

Solving using the formula,

AB = EF = √5,

BC = FG = √5,

CD = GH = √8,

DA = HE = √26,

Therefore, the length of all the sides of the polygon are the same,

Hence, the two figures are congruent.

Step-by-step explanation:

7 0
2 years ago
Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane
liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

Answer:

Rate = 0.935042^\circ /cm

Step-by-step explanation:

Given

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

T(x,y) =x\sin2y

r = 1m

v = 2m/s

Express the given point P as a unit tangent vector:

P = (\frac{1}{2}, \frac{\sqrt 3}{2})

u = \frac{\sqrt 3}{2}i - \frac{1}{2}j

Next, find the gradient of P and T using: \triangle T = \nabla T * u

Where

\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})}  = (sin \sqrt 3)i + (cos \sqrt 3)j

So: the gradient becomes:

\triangle T = \nabla T * u

\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] *  [\frac{\sqrt 3}{2}i - \frac{1}{2}j]

By vector multiplication, we have:

\triangle T = (sin \sqrt 3)*  \frac{\sqrt 3}{2} - (cos \sqrt 3)  \frac{1}{2}

\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)

\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5

\triangle T = 0.935042

Hence, the rate is:

Rate = \triangle T = 0.935042^\circ /cm

3 0
3 years ago
What number divided by -4 =64?
notka56 [123]
The number divided by -4 to get 64 was -256
6 0
3 years ago
I REALLY NEED HELP, ILL MEDAL!!!!
lara31 [8.8K]
Well, first of all, the first statement  (ABC = ADC) looks like it just says
that the two halves of the little square ... each side of the diagonal ...
are congruent.  That's no big deal, and it's no help in answering the
question.

The effect of the dilation is that all the DIMENSIONS of the square
are doubled ... each side of the square becomes twice as long.

Then, when you multiply (length x width) to get the area, you'd have

           Area = (2 x original length) x (2 x original width)

and that's
the same as      (2 x 2) x (original length x original width)

                        =     (4)  x  (original area) .


Here's an easy, useful factoid to memorize:

-- Dilate a line (1 dimension) by 'x' times . . . multiply the length by  x¹

-- Dilate a shape (2 dimensions) by 'x' . . . multiply area by  x²

-- Dilate a solid (3 dimensions) by 'x' . . . multiply volume by  x³

And that's all the dimensions we have in our world.
_______________________________

Oh, BTW . . .

-- Dilate a point (0 dimensions) by 'x' . . . multiply it by  x⁰  (1)

5 0
3 years ago
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