To do this we need to find the factors of 60 these are: 1 and 60 2 and 30 3 and 20 4 and 15 5 and 12 6 and 10 There is 1 pair that have a difference of 7 and that is 5 and 12
The value of t that makes the factor e^(.032t) have the value of 2 can be found using logarithms. 2 = e^(0.032t) ln(2) = ln(e^(0.032t)) = 0.032t t = ln(2)/0.032 ≈ 21.66