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zubka84 [21]
3 years ago
9

Use Completing the Square to convert from Standard Form to Vertex Form y=x2 – 8x + 14

Mathematics
1 answer:
Leno4ka [110]3 years ago
8 0

Answer:

(x - 4)^2 - 2

Step-by-step explanation:

Step 1: Make sure the coefficient of x^2 is 1

1 [x^2 - 8x + 14]

Step 2: Express the coefficient 8x as (8x multiplied by 1/2) the express the answer as two half's positive and negative squared

1 [x^2 - 8x + (-4)^2 - (-4)^2 + 14]

Step 3: Separate the function into two parts from the negative of the coefficient of 8x (4) solve the part then factorise the other part

1 [ ( x - 4 )^2 - 2 ]

Step 4: Distribute the factor (1)

(x + 4)^2 - 2

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3 years ago
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Describe and correct the error in writing an equation of the line shown
Rudiy27

Answer:

y  = -\frac{3}{5}x+4

Step-by-step explanation:

Given:

(x_1,y_1) = (0,4)

(x_2,y_2) = (5,1)

The attachment completes the question

From the attachment, the slope of the line was calculated as:

m = \frac{1-4}{0-5}

This step is inaccurate because the slope of a line is calculated using

m = \frac{y_2-y_1}{x_2-x_1}

Which gives

m = \frac{1-4}{5-0}

m = \frac{-3}{5}

m = -\frac{3}{5}

The line equation is then calculated using:

y -y_1 = m(x - x_1)

Substitute values for m, x1 and y1

y - 4 = -\frac{3}{5}(x - 0)

y - 4 = -\frac{3}{5}(x)

Open bracket

y - 4 = -\frac{3}{5}x

Make y the subject

y  = -\frac{3}{5}x+4

6 0
3 years ago
Round the following 8.388 to 2 decimal places
Roman55 [17]
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3 0
3 years ago
4 1/9 - 3 3/5 what is the answer to this question ?
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3 years ago
The mass of the sun is 21.3525×102921.3525×1029 kg. the mass of mercy is 328.5×1021328.5×1021 kg.how many times larger is the ma
Liono4ka [1.6K]
This is basically a simple problem to understand. The only thing that needs to be done is to divide the mass of the sun by the mass of mercury. It will give the required result.

Number of times the mass of sun is greater than
the mass of mercury =  21.3525×102921.3525×1029/<span>328.5×1021328.5×1021
                                  = </span><span>7.1783629e+15
I hope that this is the answer that you were looking for and it has come to your great help.</span>
8 0
3 years ago
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