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jekas [21]
3 years ago
14

Please please help so I can finish this

Mathematics
1 answer:
Rom4ik [11]3 years ago
5 0

RS = \sqrt{(b-0)^{2}+(c-a)^{2}} and RS is simplified to RS = \sqrt{a^{2}+b^{2}+c^{2}-2ac}

<u>Step-by-step explanation:</u>

We know that , Distance between any two points (x_1 , y_1) and (x_2, y_2) is given by formula :

Distance = \sqrt{(x_1-x_2)^{2}+(y_1-y_2)^{2}}

In this question , we have R(0,a) and S(b,c) .

We need to simplify RS which is given by:

Distance = \sqrt{(x_1-x_2)^{2}+(y_1-y_2)^{2}}

⇒ Distance = \sqrt{(x_1-x_2)^{2}+(y_1-y_2)^{2}}

⇒ RS = \sqrt{(x_1-x_2)^{2}+(y_1-y_2)^{2}}

⇒ RS = \sqrt{(0-b)^{2}+(a-c)^{2}}

⇒ RS = \sqrt{(b-0)^{2}+(c-a)^{2}}

We know that , (a-b)^{2} = a^{2}+b^{2}-2ab

⇒ RS = \sqrt{b^{2}+c^{2}+a^{2}-2ac}

⇒ RS = \sqrt{a^{2}+b^{2}+c^{2}-2ac}

∴ RS = \sqrt{(b-0)^{2}+(c-a)^{2}} and RS is simplified to RS = \sqrt{a^{2}+b^{2}+c^{2}-2ac}.

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