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Fantom [35]
3 years ago
15

In 28% of a sum is $100.80, what is the sum?

Mathematics
2 answers:
Tema [17]3 years ago
8 0

$360.00 hope this helps


Len [333]3 years ago
6 0

x= sum


.28 x=100.80

x= 100.80/.28

x=$360

the sum=$360

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Write the product as a sum: 14cos(39x)sin(19x)
charle [14.2K]

Recall that

sin(<em>a</em> + <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) + cos(<em>a</em>) sin(<em>b</em>)

sin(<em>a</em> - <em>b</em>) = sin(<em>a</em>) cos(<em>b</em>) - cos(<em>a</em>) sin(<em>b</em>)

Adding these together gives

sin(<em>a</em> + <em>b</em>) + sin(<em>a</em> - <em>b</em>) = 2 sin(<em>a</em>) cos(<em>b</em>)

To get 14 cos(39<em>x</em>) sin(19<em>x</em>) on the right side, multiply both sides by 7 and replace <em>a</em> = 19<em>x</em> and <em>b</em> = 39<em>x</em> :

7 (sin(19<em>x</em> + 39<em>x</em>) + sin(19<em>x</em> - 39<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

7 (sin(58<em>x</em>) + sin(-20<em>x</em>)) = 14 cos(39<em>x</em>) sin(19<em>x</em>)

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4 0
3 years ago
Does anyone know how to do this
Doss [256]

Answer :Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.

Step-by-step explanation:

Considering the quadrilateral with vertices

d(0,0)

i(5,5)

n(8,4)

g(7,1)

Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.

From the figure a, it is clear that the quadrilateral has

Two pairs of sides

Each pair having two equal-length sides which are adjacent

The angles being equal where the two pairs meet

Diagonals as shown in dashed lines cross at right angles,  and one of the diagonals does bisect the other - cuts equally in half

Please check the attached figure a.

4 0
3 years ago
Based on the 2009 season, the Texas Rangers have a winning percentage of .533. Use the binomial model to find the probability th
Naddik [55]

Answer:

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Here, we are given that p = 0.533.

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i.e. P(X=4)=5 \times 0.533 \times 0.048

i.e. i.e. P(X=4)=0.128

Hence, the probability of 4 wins in the next 5 games is 0.128.

8 0
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Answer:

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6 0
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