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3 years ago

8

Who was the President in 1991?

2 answers:

ser-zykov [4K]3 years ago

6 0

George H.W Bush.......................

Strike441 [17]3 years ago

6 0

Answer:

George w.h bush

Step-by-step explanation:

Who was the President in 1991?

---<u>George w.h bush</u>

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List the following numbers in order from least to greatest.<br><br>-9, -17, 7, 11, 26

Aliun [14]

Answer:

-17, -9, 7, 11, 26

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2 years ago

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1) In a yoga class, 75% of the students are women. There are 24 women in the class. How many students are in the class?

mel-nik [20]

Answer:

c

Step-by-step explanation:

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3 years ago

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3x+5=0 ‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎

strojnjashka [21]

Answer:

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Step-by-step explanation:

Move all the terms that don't contain x to the right side and solve.

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2 years ago

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evaluate the line integral ∫cf⋅dr, where f(x,y,z)=5xi−yj+zk and c is given by the vector function r(t)=⟨sint,cost,t⟩, 0≤t≤3π/2.

meriva

We have

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} \vec f(\vec r(t)) \cdot \dfrac{d\vec r}{dt} \, dt$

and

$\vec f(\vec r(t)) = 5\sin(t) \, \vec\imath - \cos(t) \, \vec\jmath + t \, \vec k$

$\vec r(t) = \sin(t)\,\vec\imath + \cos(t)\,\vec\jmath + t\,\vec k \implies \dfrac{d\vec r}{dt} = \cos(t) \, \vec\imath - \sin(t) \, \vec\jmath + \vec k$

so the line integral is equilvalent to

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (5\sin(t) \cos(t) + \sin(t)\cos(t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (6\sin(t) \cos(t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (3\sin(2t) + t) \, dt$

$\displaystyle \int_C \vec f \cdot d\vec r = \left(-\frac32 \cos(2t) + \frac12 t^2\right) \bigg_0^{\frac{3\pi}2}$

$\displaystyle \int_C \vec f \cdot d\vec r = \left(\frac32 + \frac{9\pi^2}8\right) - \left(-\frac32\right) = \boxed{3 + \frac{9\pi^2}8}$

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2 years ago

Evaluate the expression and enter your answer below.<br> 5•(4+5) - 7^2

galben [10]

Answer:

Yes

Step-by-step explanation:

5 0

3 years ago