Answer: z score = 0.00714
Step-by-step explanation: the value of test statistics is gotten using the standard normal distribution table.
Z= 2.45 has area to the left (z<2.45) and area to the right (z>2.45).
Level of significance α is the probability of committing a type 1 error. The area under the distribution is known as the rejection region and it is the area towards the right of the distribution.
The table I'm using is towards the left of the distribution.
But z>2.45 + z<2.45 = 1
z> 2.45 = 1 - z<2.45
But z < 2.45 = 0.99286
z > 2.45 = 1 - 0.99286
z >2.45 = 0.00714
Hence the test statistics that would produce the least type 1 error is 0.00714
You can use a tangent:
We have opposite = 17 and adjacent = x.
substitute:
cross multiply
multiply both sides by √3
divide both sides by 3
Use the Pythagorean theorem:
-------------------------------------------------------------------------------------------------
Other method.
triangle.
The sides are in the ratio 
Therefore
Answer:
Solutions: 
, 
Step-by-step explanation:
Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:
Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:
, 
Therefore, the solutions to the given quadratic equation are:
, 
If P=$10, MPL= $25 and APL=$ 40, then the value of marginal product of labor is $250
The marginal product of labor (MPL) is the change in output that results from employing an added unit of labor.
The average product of labor (APL) is the total product of labor divided by the number of units of labor employed.
Here,
P= $10
The marginal product of labor (MPL)= $25
The average product of labor (APL)= $40
The value of marginal product of labor= P × The marginal product of labor (MPL)
The value of marginal product of labor= 10×25=$250
Hence, If P=$10, MPL= $25 and APL=$ 40, then the value of marginal product of labor is $250
Learn more about the value of marginal product of labor here
brainly.com/question/15072173
#SPJ4
Answer:
In the pic
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask me in the comments below =)
