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dmitriy555 [2]
3 years ago
8

Rational number 7/3 has terminating decimal

Mathematics
1 answer:
vfiekz [6]3 years ago
5 0

Answer:

2.33

Step-by-step explanation:

Plug "7/3" in your calculator and round to the nearest hundredth (by finding the hundredth's place, looking at the digit before it, and moving the hundredth's place up one value if you deciphering that the digit before is greater/equal to 5). If you need a terminating decimal, you need to round. If you don't need it as a terminating decimal, add a ling over the last digit where the decimal begins to repeat.

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Mel randomly selects a coin 150 times selecting a dime 30 times, the experimental probability is 1/5 what is the theoretical pro
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Answer:

Step-by-step explanation:

We can calculate probability by looking at the outcomes of an experiment or by reasoning What is the theoretical probability that a fair coin lands on heads? Choose 1 answer:  Random numbers for experimental probability. This means that if we roll a die 60 times we can expect each of the six faces to come up.

Hope this helps.

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(PLEASE HELP) Chloe has 40 lollipops of these lollipops 15 of them are blue and the rest are red what is the ratio of the number
statuscvo [17]

Answer:

25:15

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Enter the explicit rule for the geometric sequence.<br><br> 9,6,4,83,…
soldier1979 [14.2K]

Answer:

a_n = 2^(n - 1) 3^(3 - n)


Step-by-step explanation:

9,6,4,8/3,…

a1 = 3^2

a2 = 3 * 2

a3 = 2^2

As we can see, the 3 ^x is decreasing and the 2^ y is increasing

We need to play with the exponent in terms of n

Lets look at the exponent for the base of 2

a1 = 3^2  2^0

a2 = 3^1   2^1

a3 =    3^ 0 2^2

an =   3^      2^(n-1)

I picked n-1  because that is where it starts  0

 n = 1   (1-1) =0

  n=2   (2-1) =1

  n=3  (3-1) =2

Now we need to figure out the exponent for the 3 base

I will pick (3-n)

n =1  (3-1) =2

n =2  (3-2) =1

n=3    (3-3) =0

8 0
3 years ago
Find the parametric equations for the line that is tangent to the given curve at the given parameter (3cost)i (t^4 -3sint)j
ale4655 [162]

Answer:

Following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

In the given equation, when the point t=0

So,

\to r(0) = (3 \cos 0)i + (0^4 - 6 \sin 0)j + (2e^{3\times 0})k)

           = (3 \times 1)i + (0 - 0)j + (2e^{0})k)\\\\ = 3i +  0j + (2 \times 1)k)\\\\ = 3i +  0j + 2k \\

The value of the coordinates are 3, 0, 2 . so, the equation of the line is:

\to \frac{(x-3)}{3 \cos \ t} = \frac{(y-0)}{(t^{4}-6 \sin \ t)} = \frac{(z-2)}{2e^{3t}}=k

5 0
3 years ago
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