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ikadub [295]
3 years ago
6

Evaluate the function for x = -4n.

Mathematics
2 answers:
larisa [96]3 years ago
8 0
I think it’s c is the answer
gregori [183]3 years ago
5 0
C is the correct one
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9. Miguel measures 5 kg of rice. One kilogram is approximately equal to 2.2 pounds. Which
Nitella [24]

Answer: 11

Step-by-step explanation:

One kilogram is equal to 2.2 pounds so all you would have to do is multiply 2.2 x 5 and you get 11. :)

8 0
3 years ago
A team of cancer research specialists received a grant of $500,000 to be used for cancer research. They deposited some of the mo
Llana [10]

Answer:

  • $450,000 at 10%
  • $50,000 at 9%

Step-by-step explanation:

Let x represent the amount invested at 10%. Then the total interest earned per year is ...

  0.10x + 0.09(500,000-x) = 49,500

  0.01x = 49500 -45000

  x = 4500/0.01 = 450,000

$450,000 was deposited in the 10% account; $50,000 was deposited in the 9% account.

5 0
3 years ago
The graph of the equation y=|x+5| is shifted 2 units up and 6 units to the right. Rewrite the equation of the new graph for the
DerKrebs [107]

Answer:

Step-by-step explanation:

To move the graph 6 units to the right, subtract 6 in the absolute value.

y=|x+5-6|

To move it up, add 2 outside the absolute value.

y=|x+5-6|+2

Now remove the absolute values since x>1.

y=x+5-6+2

y=x+1

4 0
3 years ago
Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab
Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

<u>Right part:</u>

\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

Since simplified left and right parts are the same, then the equality is true.

3 0
3 years ago
Help please if you can
antiseptic1488 [7]
What is the question?

6 0
3 years ago
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