Answer:
Number of two point goals = 169
Number of three point goals = 123
Number of free throws = 139
Step-by-step explanation:
Let the number of two point goals = 
Let the number of three point goals = 
Let the number of free throws = 
As per the given statements:


Using equation (1):
...... (3)
Total number of points from two point goals = 
Total number of points from three point goals = 
Total number of points from free throws = 

using (1) and (3):

By (1):

By (3):

So, answers are:
Number of two point goals = 169
Number of three point goals = 123
Number of free throws = 139
You divide 12 by 1.56 because a dozen is 12 of something. This gives you about 8 cents per
Answer: For the sum of 130
First: $90
Second: $40
Step-by-step explanation:
We write equations for each part of this situation.
<u>The Total Charge</u>
Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.
<u>The Sum of the Rates</u>
Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.
We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.
For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.
15a + 5 (130-a)=1550
15a+650-5a=1550
10a+650-650=1550-650
10a=900
a=$90 was charged by the first mechanic.
We substitute to find the second mechanic's rate.
90+b=130
90-90+b=130-90
b= $40 was charged by the second mechanic
The value of x = 18
explanation:
12/x = 6/9
x = 18
Answer:
The sample space for selecting the group to test contains <u>2,300</u> elementary events.
Step-by-step explanation:
There are a total of <em>N</em> = 25 aluminum castings.
Of these 25 aluminum castings, <em>n</em>₁ = 4 castings are defective (D) and <em>n</em>₂ = 21 are good (G).
It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.
In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.
The formula to compute the combinations of k items from n is given by the formula:

Compute the number of samples that are possible as follows:


The sample space for selecting the group to test contains <u>2,300</u> elementary events.