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polet [3.4K]
3 years ago
7

###Please Help### for f(x)=1/x-5 and g(x)=x^2+2 Find the expression for g(x)

Mathematics
1 answer:
Bond [772]3 years ago
8 0

Answer:

I don't get it

Step-by-step explanation:

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Pls help math esperts
MaRussiya [10]

Answer:

Jackson spent $4.25 on his lunch

Step-by-step explanation:

because $6.50- $2.25 is $4.25

6 0
3 years ago
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Find the slope of the line that passes through (1,6) and (4,4)
Vadim26 [7]

Answer:

y=-2/3x+20/3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(4-6)/(4-1)

m=-2/3

y-y1=m(x-x1)

y-6=-2/3(x-1)

y=-2/3x+2/3+6

y=-2/3x+2/3+18/3

y=-2/3x+20/3

8 0
3 years ago
Find the volume of the following solid. The solid between the cylinder ​f(x,y)equals=e Superscript negative xe−x and the region
PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy

Now evaluate,

\int_{0}^{ln(6)}e^{-x}dx

which evaluates to,  5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

\int_{-6}^{6}\frac{5}{6}dy = 10

So,

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10

7 0
3 years ago
Free brainliest for first to answerrr . check my questions on my profile for more like this !
Elena L [17]
Am I supposed to answer anything lol
6 0
2 years ago
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Find volume of triangular pyramid or prism.
almond37 [142]

I hope this helps you

5 0
4 years ago
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