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zloy xaker [14]
3 years ago
9

Please help will name brainliest: Make y the subject of the formula x=a-2by²

Mathematics
2 answers:
lozanna [386]3 years ago
4 0

Answer:

y = ± \sqrt{\frac{a-x}{2b} }

Step-by-step explanation:

Given

x = a - 2by² ( add 2by² to both sides )

x + 2by² = a ( subtract x from both sides )

2by² = a - x ( divide both sides by 2b )

y² = \frac{a-x}{2b} ( take the square root of both sides )

y = ± \sqrt{\frac{a-x}{2b} }

Alenkasestr [34]3 years ago
4 0

Answer:

y = a - x  \di2b

Step-by-step explanation:

2b {y }^{2}  = a - x

2b {y}^{2} \div 2b = a - x \ \div  2b

{y}^{2}  = a - x \div 2b

y =  \sqrt{a - x \div 2b}

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marusya05 [52]
Manze fou zo ou poum jo
4 0
3 years ago
In this triangle, side AT = 24. Please give the value for the sine, cosine, and tangent for this diagram (Which is the marked an
sashaice [31]
The value  of the sine, cosine and tangent of the figure will be found as follows:
a] Sine
sin x=(opposite)/(hypotenuse)
opposite=7
hypotenuse=25
thus:
sin x=  7/25  

 b] Cosine
cos x=adjacent/hypotensue
adjacent=24
hypotenuse=25
cos x=24/25

Tangent
Tan x=opposite/adajcent
opposite=7
adjacent=24
thus
tan x=7/24

5 0
3 years ago
What is the area of the composite figure
oksano4ka [1.4K]

Answer:

C

Step-by-step explanation:

To find the area of a composite figure, separate it into the regular parts which make the irregular shape. This shape is composed of a semi-circle and a rectangle. Find the area by finding the area of each shape.

Semi-circle:

The semi-circle has a diameter of 2 + 4 + 2 = 8. The area this figure uses the radius which is half the diameter. The radius is 4. To find the area substitute r = 4 into \pi r^2 = \pi 4^2 = 16\pi. However the semi-circle has a smaller circle cut out of it with radius 2. The area of the smaller circle is \pir^2 = \pi 2^2=4\pi. The semi circle in the shape is the areas subtracted which equals 12π.

Rectangle:

The area of the rectangle is found using A = b*h = 2*5 = 10.

The total area is 12π + 10 meters squared.

5 0
3 years ago
Please help<br><br><br>A) x= -4 and 4<br><br>B) x=4 and 6<br><br>C) x=2 and 8<br><br>D) no solution
Neporo4naja [7]

Answer:

No solutions

Step-by-step explanation:

|-2x-10| + 4 = 2

Subtract 4 from each side

|-2x-10| + 4-4 = 2-4

|-2x-10|  = -2

The absolute value is negative so there are no solutions.

Absolute values are always positive, so they cannot be negative.


4 0
3 years ago
Y=-5x+6<br> y=3x-2<br><br> Find the solution to the system of equations.
Kobotan [32]

Answer:

(1, 1 )

Step-by-step explanation:

Given the 2 equations

y = - 5x + 6 → (1)

y = 3x - 2 → (2)

Since both equations express y in terms of x, equate the right sides

3x - 2 = - 5x + 6 ( add 5x to both sides )

8x - 2 = 6 ( add 2 to both sides )

8x = 8 ( divide both sides by 8 )

x = 1

Substitute x = 1 into either of the 2 equations for corresponding value of y

Substituting x = 1 in (2)

y = 3(1) - 2 = 3 - 2 = 1

Solution is (1, 1 )

4 0
3 years ago
Read 2 more answers
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