We conclude that the distance between points C and D is 5 units.
<h3>
How to find the distance between the two points?</h3>
Remember that if we have two points (x₁, y₁) and (x₂, y₂), the distance between these points is:
d = √( (x₂ - x₁)^2 + (y₂ - y₁)^2)
In this case, we know that:
Point C has the coordinates (-1, 4)
Point D has the coordinates (2, 0)
Then the distance between these two points is:
d = √( (-1 - 2)^2 + (0 - 4)^2) = √25 = 5
We conclude that the distance between points C and D is 5 units.
If you want to learn more about distance between points:
brainly.com/question/7243416
#SPJ1
<h3>
Answer: 9/41</h3>
==========================================================
Explanation:
We have a triangle with these three sides.
Use the pythagorean theorem to find b
a^2+b^2 = c^2
b = sqrt(c^2 - a^2)
b = sqrt(82^2 - 80^2)
b = sqrt(324)
b = 18
This is the missing vertical leg of the triangle. And this is also the side opposite angle C.
We have enough information to compute the sine of the angle.
sin(angle) = opposite/hypotenuse
sin(C) = AB/AC
sin(C) = 18/82
sin(C) = (9*2)/(41*2)
sin(C) = 9/41
Answer:
50°
Step-by-step explanation:
I am assuming that the shape is a right triangle.
All interior angles of a triangle add up to 180°.

The missing angle should be 50°.
Hope this helps.
Answer:

Step-by-step explanation:

![As\ range=51,\\x-4=51\\x=51+4\ [Adding\ 4\ on\ both\ the\ sides]\\x=55 \\2. x\ is\ the\ lowest\ observation\ or\ x](https://tex.z-dn.net/?f=As%5C%20range%3D51%2C%5C%5Cx-4%3D51%5C%5Cx%3D51%2B4%5C%20%5BAdding%5C%204%5C%20on%5C%20both%5C%20the%5C%20sides%5D%5C%5Cx%3D55%20%5C%5C2.%20x%5C%20is%5C%20the%5C%20lowest%5C%20observation%5C%20or%5C%20x%3C4.%5C%5CHence%2C%5C%5CHighest%5C%20observation%3D48%5C%5CLowest%5C%20observation%3Dx%5C%5CHence%2C%5C%5CAs%5C%20the%5C%20range%5C%20is%5C%2051%2C%5C%5C48-x%3D51%5C%5C-x%3D51-48%20%5BSubtracting%5C%2048%5C%20from%5C%20both%5C%20the%5C%20sides%5D%5C%5C-x%3D3%5C%5Cx%3D-3)