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kkurt [141]
4 years ago
14

How many arrangements are there letters of the word Fred

Mathematics
2 answers:
Anastasy [175]4 years ago
5 0

Answer:

24 (assuming the arrangements are 4 letters)

Step-by-step explanation:

There are 4 different possibilities for the first letter, 3 for the second, 2 for the third, and 1 for the fourth.

4x3x2x1=24

Nady [450]4 years ago
5 0

i think 24...heh T^T

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Mr.Brown has 110 fiction books and 90 non-fiction books on his shelf. what percent of her library is non fiction?
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45%

Step-by-step explanation:

Given

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Number of non fiction books = 90

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90/200 x 100%

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A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner
frozen [14]

Answer:

I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner I_{corner} is:

I_{corner} = \int\limits \int\limits_R (x^2+y^2)  \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx

where :

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I_{corner} =  \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx

I_{corner} =  \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx

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Thus; the moment of inertia of the lamina about one corner is I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)

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