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3 years ago

2. Given the expression f(g(k(x))), where f, g, and k are functions, what operation should be

Mathematics

2 answers:

Allushta [10]3 years ago

7 0

Answer:

You must start with the innermost function.

First you evaluate k(x). Then you evaluate g(k(x)).

Finally you evaluate f(g(k(x))).

The order does matter. If you evaluate in a different order, you will be inputting wrong numbers into each subsequent function generating an incorrect answer.

mestny [16]3 years ago

6 0

Answer:

The order matters

Step-by-step explanation:

If you answer it in a different order, you will be inputting wrong numbers into each subsequent function generating an incorrect answer.

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Rob notices that 55 percent of the people leaving the supermarket chhose plastic bags instead of paper bags. out of 600 people,

Bumek [7]

To solve this answer, you are trying to find 55% of 600, because that is the number of people who chose plastic bag.

55% can be re-written as 55/100 OR 0.55 since percentages are always out of 100.

So, we do 0.55*600, which gives us 330. 330 people carry plastic bags.

5 0

3 years ago

2. Find the volume of the prism. Round to the nearest tenth.

natita [175]

$\huge\mathcal\pink{ANSWER}$

$\mathsf \purple{ v = \frac{1}{2} (a + b) \times h \times l}$

$\mathsf \pink{v = \frac{1}{2} (5 + 12) \times 6.1 \times 16}$

$\mathsf \purple{v = \frac{1}{2} (17) \times 6.1 \times 16}$

$\mathsf \pink{v = 8 \frac{1}{2} \times 6.1 \times 16}$

$\mathsf \purple{v = 829.6 {mi}^{3} }$

7 0

2 years ago

A professor pays 25 cents for each blackboard error made in lecture to the student who pointsout the error. In a career ofnyears

marta [7]

Answer:

(a) The probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b) n = 28.09

Step-by-step explanation:

The random variable Yₙ is defined as the total numbers of dollars paid in n years.

It is provided that Yₙ can be approximated by a Gaussian distribution, also known as Normal distribution.

The mean and standard deviation of Yₙ are:

$\mu_{Y_{n}}=40n\\\sigma_{Y_{n}}=\sqrt{100n}$

(a)

For n = 20 the mean and standard deviation of Y₂₀ are:

$\mu_{Y_{n}}=40n=40\times20=800\\\sigma_{Y_{n}}=\sqrt{100n}=\sqrt{100\times20}=44.72\\$

Compute the probability that Y₂₀ exceeds 1000 as follows:

$P(Y_{n}>1000)=P(\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}>\frac{1000-800}{44.72})\\=P(Z> 4.47)\\=1-P(Z$

**Use a z table for probability.

Thus, the probability that Y₂₀ exceeds 1000 is 3.91 × 10⁻⁶.

(b)

It is provided that P (Yₙ > 1000) > 0.99.

$P(Y_{n}>1000)=0.99\\1-P(Y_{n}$

The value of z for which P (Z < z) = 0.01 is 2.33.

Compute the value of n as follows:

$z=\frac{Y_{n}-\mu_{Y_{n}}}{\sigma_{Y_{n}}}\\2.33=\frac{1000-40n}{\sqrt{100n}}\\2.33=\frac{100}{\sqrt{n}}-4\sqrt{n} \\2.33=\frac{100-4n}{\sqrt{n}} \\5.4289=\frac{(100-4n)^{2}}{n}\\5.4289=\frac{10000+16n^{2}-800n}{n}\\5.4289n=10000+16n^{2}-800n\\16n^{2}-805.4289n+10000=0$

The last equation is a quadratic equation.

The roots of a quadratic equation are:

$n=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

a = 16

b = -805.4289

c = 10000

On solving the last equation the value of n = 28.09.

8 0

3 years ago

Slove for t : /3t - 6/=12

koban [17]

Answer:

6 or -2

Step-by-step explanation:

|3t - 6| = 12

3t - 6 = 12

3t = 18

t = 6

3t - 6 = -12

3t = -6

t = -2

4 0

2 years ago

Is 2/8 greater or less than 1/4

Alex17521 [72]

Its neither 2/8 is 1/4 simplified, therefore 2/8 is = 1/4

Hope this helped!

4 0

3 years ago

Read 2 more answers