A rotating beacon is located 1 kilometer off a straight shoreline. If the beacon rotates at a rate of 3 revolutions per minute,
how fast (in kilometers per hour) does the beam of light appear to be moving to a viewer who is 1/2 kilometer down the shoreline?
1 answer:
Find the radius of the circle by finding the distance between the viewer and the beacon.
then find the circumference by using 2πr2
this will be the distance the light covers over 1 revolution.
then using dimensional analysis:
3 rev/min (7.037 km/rev) (60 min/1 hr) = 1266.7 km/hr
You might be interested in
Your equation should be 5 - r + 2 = 3.
Answer:B
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
So that is a 90 degree angle and there is an angle of 30. 30-90 is 60. 60 divided by 4 is 15. So thus the answer is A,15.
-3 and -16 multiply to 48 since negatives cancel and add to -19
Answer:
3/4 x 5 = 15/20
3/5 x 4 = 12/20
15/20 + 12/20 = 27/20
Hope this helps!