Answer:
Step-by-step explanation:
Average speed = distance/time
Trip to dry dock
Let x be the velocity
Time = 2hours
Distance = average speed ×time
Distance = x×2
Distance = 2x
Return trip
Velocity = x-5 (5 miles per hour faster on the trip there than on the return trip)
Time = 3hrs
Distance = 3(x-5)
Since the distance is the same both to and fro;
2x = 3(x-5)
2x = 3x -15
2x-3x = -15
-x = 15
x = 15
Hence the aircraft carrier's average speed on the outbound trip is 15miles/hour
Answer:
-13
Step-by-step explanation:
f(x)=-3-10
f(x)=-13
Answer:
15,999264824
Step-by-step explanation:
According to the Order of Operations [GEMS\BOMDAS\PEMDAS etc.], Division and Multiplication are done from left to right as you see it, so first, you divide 16 by 3,48216, which is 4,5948491741, then you multiply that by 3,482 to get 15,999264824.
I am joyous to assist you anytime.
Answer:
Step-by-step explanation:
2Y^5 . Y^3
it means 2Y^5 X Y^3
ans=2Y^8
I think it is the answer
First we want to subtract 58.50 by 45.00. what is the answer