Answer:
3x -2y = -14
Step-by-step explanation:
The parallel line will have a new constant that can be found by substituting the given point for x and y.
-3x +2y = -3(0) +2(7) = 14
An equation for the parallel line is ...
-3x +2y = 14
__
In standard form, the leading coefficient is positive, so the standard form equation is ...
3x -2y = -14
Answer:
140
Step-by-step explanation:
Answer:
-8
Step-by-step explanation:
x^(m/n)=![\sqrt[n]{x}^m](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%5Em)
(-32)^(3/5)
=![\sqrt[5]{(-32)} ^3](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B%28-32%29%7D%20%5E3)
=(-2)^3
=-8
Answer:
Bk = 65
Step-by-step explanation:
BK as we can see is 4x + 1
If two triangles are similar, the ratio of the corresponding sides are the same
Thus;
2x+7/27 = 4x + 1/45
45(2x + 7) = 27(4x + 1)
90x + 315 = 108x + 27
108x-90x = 315-27
18x = 288
x = 288/18
x = 16
From the question;
BK = 4x + 1
BK = 4(16) + 1
BK = 64 + 1
BK = 65
Answer:
285,753 cm³/min
Step-by-step explanation:
The rate of change of volume is the product of the water's surface area and its rate of change of depth.
At a depth of 2 m, the water has filled 1/3 of the 6 m depth of the tank. So, the radius at the water's surface will be 1/3 of the tank's radius of 2 m. The water's surface area is ...
A = πr² = π(2/3 m)² = 4π/9 m²
The rate of change of depth is 0.2 m/min, so the volume of water is increasing at the rate ...
dV/dt = (0.20 m/min)(4π/9 m²) = 8π/90 m³/min ≈ 279253 cm³/min
This change in volume is the difference between the rate at which water is being pumped in and the rate at which it is leaking out:
2.8×10⁵ cm³/min = (input rate) - 6500 cm³/min
Adding 6500 cm³/min to the equation, we get ...
input rate ≈ 285,753 cm³/min
