Answer:
Right Isosceles
Step-by-step explanation:
First, let's see if this triangle is Acute, Obtuse or Right.
We see that PB and QB are perpendicular lines, meaning that they form a right angle. Therefore, triangle PQB is a right triangle.
Next, let's see if this triangle is equilateral, isosceles or scalene. PB and QB are congruent side lengths but PQ is not congruent to either PB or QB. Therefore, because two of the side lengths are congruent to each other and one is not, then triangle PQB is a isosceles triangle.
In conclusion, triangle PQB can be categorized as a right isosceles triangle.
Hope this helps!
Answer:
If the dimension increased by doubled, tripled or quadrupled, then it will be 2x, 3x, or 4x for each dimension.
Answer:
18
Step-by-step explanation:
Let x represent smallest number and y represent second number.
We have been given that the biggest among three numbers is 2.4 larger than the smallest one. So biggest number would be 
.
We are also told that 15 times the smallest one is equal to 12 times the second and 10 times the third. We can represent this information in equations as:
Upon solving 2nd equation, we will get:
Therefore, the smallest number is 4.8.
The biggest number would be 
.
Upon substituting in equation (1), we will get:
Therefore, 2nd number would be 6.
Let us find sum of all numbers as:
Therefore, the sum of all 3 numbers would be 18.
The equation that can be used to determine the original length of the pool is 205.85 = 11.6(l + 3.7)
Let l be the original length of the pool.
Since the length of the pool is increased by 3.7 m, the new length L = l + 3.7.
Also, the area of the pool A = 205.85 square meter and it is a rectangle with width, W = 11.6 meters,
So, A = LW
Substituting the values of the variables into the equation, we have
A = LW
205.85 = (l + 3.7)11.6
So, the equation that can be used to determine the original length of the pool is 205.85 = 11.6(l + 3.7)
Learn more:
brainly.com/question/12932084
64 and 28 have a GCF of 4, since 64 = 4 x 16, 28 = 4 x 7, and 7 and 16 have no factors other than 1 in common. Knowing that, we can rewrite 64 + 28 as
4 x 16 + 4 x 7
and then use the distributive property to rewrite it again as
4 x (16 + 7)
