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TiliK225 [7]
3 years ago
5

Find the volume of both shapes please answer will give brainiest Also please answer neatly.

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
6 0

Answer:

2). Volume = 14400 feet³

3). Volume = 157.5 ft³

Step-by-step explanation:

Both the figures given in the sheet attached are a rectangular pyramid and a triangular prism.

2). In this part of the question solid given is in the shape of an rectangular pyramid.

Volume of this oblique pyramid = \frac{1}{3}(\text{Base})(\text{Height})

Here 'B' = area of the base

h = height of the pyramid

Volume = \frac{1}{3}(25\times 36)\times 48

             = 14400 cubic feet

4). Volume of a triangular cone = (Area of the triangular base)×(height)

                                                    = [\frac{1}{2}(\text{Base})(\text{height})]\times {\text{height of the prism}}

                                                    = \frac{1}{2}(7\times 9)\times {5}

                                                    = 157.5 ft³

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Answer:

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Step-by-step explanation:

\frac{2}{3} + \frac{x}{3} > 1 ( multiply through by 3 to clear the fractions )

2 + x > 3 ( subtract 2 from both sides )

x > 1

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Step-by-step explanation:

i.1+y<25

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13 lb7 oz <br> + 10 lb2 oz
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6 0
3 years ago
Please help
Alekssandra [29.7K]

Answer:

25 in x 15 in

Step-by-step explanation:

Given:

  • Length = 3/5 the width
  • Area = 375 in²

Let width = x

Therefore, length = 3/5 x

First create an equation for the area of the picture based on the given information for its width and length:

\begin{aligned} \implies \textsf{Area of original picture} & = \sf width \times length\\& = x\left(\dfrac{3}{5}x\right)\\& = \dfrac{3}{5}x^2\end{aligned}

We are told the area of the enlarged picture is 375 in².  Therefore, substitute this into the equation and solve for x to find the width of the enlarged picture:

\begin{aligned}\textsf{Area} & = 375\\ \implies \dfrac{3}{5}x^2 & = 375\\ x^2 & =375 \cdot \dfrac{5}{3}\\ x^2 & =625\\ x & = \sqrt{625}\\ x& = 25\end{aligned}

Therefore, the width of the enlarged picture is 25 in.

Substitute the found value of x into the expression for length to find the length of the enlarged picture:

\begin{aligned}\sf Length & = \dfrac{3}{5}x\\\\\implies \sf Length & = \dfrac{3}{5}(25)\\\\& = 15\: \sf in\end{aligned}

Therefore, the dimensions of the enlarged picture are <u>25 in x 15 in</u>.  The width is 25 in and the length is 15 in, as the length is 3/5 of the width.

5 0
2 years ago
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