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galben [10]
3 years ago
11

Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.

Mathematics
2 answers:
lys-0071 [83]3 years ago
3 0

<em>Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work. </em>

<em>But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.</em>

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as x^2+5x-2 after dividing   2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2 by 2x^2\:-\:3x\:+\:1  , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

                            2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2

Lets divide the expression by 2x^2\:-\:3x\:+\:1

Solution Steps:

\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}

Factorizing

2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)

\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}

Factorizing

2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)

\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}

\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2

x^2+5x-2

Thus,

\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as x^2+5x-2 after dividing   2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2 by 2x^2\:-\:3x\:+\:1  , would be the one who solved it correctly.

Keywords: expression, division

Learn more about expression division from brainly.com/question/1575482

#learnwithBrainly

kramer3 years ago
3 0

Answer:

B. Clyde’s work is correct because Tamara did not subtract the terms correctly.

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