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3 years ago

If g(x)=x^2-5x+8, find g(8)

Mathematics

1 answer:

ycow [4]3 years ago

5 0

Answer:

Option A) 32

Step-by-step explanation:

Given the quadratic function, g(x) = x²- 5x + 8:

In order to evaluate and determine the output value given g(8), substitute the input value into the function:

g(x) = x²- 5x + 8

g(8) = (8)²- 5(8) + 8

g(8) = 64 - 40 + 8

g(8) = 32

Therefore, the correct answer is Option A) 32.

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A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

3 years ago

The legs of a right triangle measure 6 centimeters and 8 centimeters. How long is the hypotenuse in centimeters?

klemol [59]

Answer:

10cm ( A )

Step-by-step explanation:

This would use the Pythagorean Theorem. That means it would be -

a^2_b^2= c^2, in this case, you have 2 of your legs already so those two values would be a&b. you would stick those two into the equation and it should look like this:

6^2+8^2=c^2

then 36+64=c

and then 100=c

after that, you would take the square root of c to get

10!

8 0

3 years ago

Read 2 more answers

A 2b (3 a 2 + 4 ab 2 )

Gala2k [10]

Answer:

You should get 13