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2 years ago

Plz help this is due in 1 hour. 56a = 7/4. What is a?

Mathematics

2 answers:

jolli1 [7]2 years ago

8 0

56a=7/4

multiply 56 to the other side, and then multiply 56 times 4 to get 224 and then add seven to get your answer which is 231.

elena-s [515]2 years ago

5 0

To get a you have to have a on its own side
56a=7/4
divide 56 on both sides
a=56/1 divided by 4/7 (switch 7/4 to 4/7 because you are going from division to multiplication)
a=32
Hope this helped

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frosja888 [35]

Answer:

1 5 10 10 5 1 Row 5

1 6 15 20 15 6 1 Row 6

Recursive relationship:

Each row has number of positions = row number + 1. The Row 0 is always 1.

The first and last number in each row is 1, the number in the second position and the penultimate corresponds to the number of the row. The middle numbers correspond to the sum of the two numbers in the top row. The resulting number from the addition is located in the middle of the numbers added in the next row.

Step-by-step explanation:

The pascal's triangle

* Row 0 = 1

* Row 1 = 1 1

1 Row 0

1 1 Row 1

Since there are only two positions, the first and last are 1.

*Row 2 = 1 _ 1

1 Row 0

1 1 Row 1

1 2 1 Row 2

2 is the sum of 1 + 1 and we place it in the next row between the added numbers 1 and 1.

* Row 3 = 1 _ _ 1

1 Row 0

1 1 Row 1

1 2 1 Row 2

1 3 3 1 Row 3

1 + 2 = 3 (the row number and the and adding the numbers from the previous row)

* Row 4 = 1 _ _ _ 1

1 Row 0

1 1 Row 1

1 2 1 Row 2

1 3 3 1 Row 3

1 4 6 4 1 Row 4

1 + 3 = 4 (the row number)

3 +3 = 6

* Row 5 = 1 _ _ _ _ 1

1 Row 0

1 1 Row 1

1 2 1 Row 2

1 3 3 1 Row 3

1 4 6 4 1 Row 4

1 5 10 10 5 1 Row 5

1 + 4 = 5

4 + 6 = 10

* Row 6 = 1 _ _ _ _ _ 1

1 Row 0

1 1 Row 1

1 2 1 Row 2

1 3 3 1 Row 3

1 4 6 4 1 Row 4

1 5 10 10 5 1 Row 5

1 6 15 20 15 6 1 Row 6

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

improper to mixed number

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mote1985 [20]

Answer:

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Step-by-step explanation:

We need to use the quadratic formula to find the solutions for

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(Note: quadratic formula is used when x^2 is in the equation. So considering 3x^2 instead of 3x^3)

The quadratic formula is: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

From the given equation $y = 3x^3 + 8x - 1$ we have a =3, b=8 and c =-1

Putting values in the formula and finding solutions:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-8\pm\sqrt{(8)^2-4(3)(-1)}}{2(3)}\\x=\frac{-8\pm\sqrt{64+12}}{6}\\x=\frac{-8\pm\sqrt{76}}{6}\\x=\frac{-8\pm8.71}{6}\\x=\frac{-8+8.71}{6}\:or\:x=\frac{-8-8.71}{6}\\x=0.119\:or\:x=-2.785$

So, Solving the equation using quadratic formula we get $\mathbf{x=0.119\:or\:x=-2.785}$

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