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rodikova [14]
4 years ago
14

Rachel traveled to five different areas (A, B, C, D, and E) to study the number of buckeye butterflies and the number of monarch

butterflies living there. The table shows her findings. Area Buckeye Butterflies Monarch Butterflies A 15 16 B 27 36 C 12 25 D 24 32 E 44 33 .The relationship between the number of buckeye butterflies and the number of monarch butterflies is not proportional across all areas. Which two areas have buckeyes and monarchs in the same proportion?
areas C and E
areas B and D
areas C and D
NextReset
Mathematics
2 answers:
vesna_86 [32]4 years ago
8 0

B, and D. It took me more than a half-hour to figure it out! LOL

tangare [24]4 years ago
3 0
Areas B and D have buckeyes and monarchs in the same proportion 
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If the graph of y=f(x) passes through the point (0,1), and dy/dx=xsin(x^2)/y, then f(x)= ?
Zigmanuir [339]

The differential equation

d<em>y</em>/d<em>x</em> = <em>x</em> sin(<em>x</em> ²) / <em>y</em>

is separable as

<em>y</em> d<em>y</em> = <em>x</em> sin(<em>x</em> ²) d<em>x</em>

Integrate both sides:

∫ <em>y</em> d<em>y</em> = ∫ <em>x</em> sin(<em>x</em> ²) d<em>x</em>

∫ <em>y</em> d<em>y</em> = 1/2 ∫ 2<em>x</em> sin(<em>x</em> ²) d<em>x</em>

∫ <em>y</em> d<em>y</em> = 1/2 ∫ sin(<em>x</em> ²) d(<em>x</em> ²)

1/2 <em>y</em> ² = -1/2 cos(<em>x</em> ²) + <em>C</em>

Solve for <em>y</em> implicitly:

<em>y</em> ² = -cos(<em>x</em> ²) + <em>C</em>

Given that <em>y</em> = 1 when <em>x</em> = 0, we get

1² = -cos(0²) + <em>C</em>

1 = -cos(0) + <em>C</em>

1 = -1 + <em>C</em>

<em>C</em> = 2

Then the particular solution to the DE is

<em>y</em> ² = 2 - cos(<em>x</em> ²)

Solving explicitly for <em>y</em> would give two solutions,

<em>y</em> = ± √(2 - cos(<em>x</em> ²))

but only the one with the positive square root satisfies the initial condition:

√(2 - cos(0²)) = √1 = 1

-√(2 - cos(0²)) = -√1 = -1 ≠ 1

So the unique solution to this DE is

<em>y</em> = √(2 - cos(<em>x</em> ²))

4 0
3 years ago
How to do this question
Bas_tet [7]

Answer:

x

Step-by-step explanation:

factor out both equations and then cancel any of the common factors. You should be left with 4x/4, which simplified is x

7 0
2 years ago
PLEASE HELP ASAP MARK AS BRAINLIEST
MatroZZZ [7]
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3 years ago
Find the point P on the line y=2x that is closest to the point (20,0) .what is the least distance between pans (20,0)?
Vsevolod [243]
The closest point on a line, to another point, will be a point that's on a normal of that line, or a line that is perpendicular to it, notice picture below

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so, we know that line passes through the point 20,0, and has a slope of -1/2

if we plug that in the point-slope form, we get \bf y-0=-\cfrac{1}{2}(x-20)\implies y=-\cfrac{1}{2}x+10

now, the point that's on 2x and is also on that perpendicular line, is the closest to 20,0 from 2x, thus, is where both graphs intersect, as you can see in the graph

thus  \bf 2x=-\cfrac{1}{2}x+10  solve for "x'

------------------------------------------------------------

not sure on the 2nd part, but sounds like, what's the distance from that point to 20,0, well, if that's the case, just use the distance equation

\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ \square }}\quad ,&{{ \square }})\quad &#10;%  (c,d)&#10;&({{ \square }}\quad ,&{{ \square }})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}


6 0
3 years ago
Please help me with #14 and #15
RSB [31]
What is 14 and 15 tell me 
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