Can someone help me real quick

Given sin (-∅) = -1/4 and tan∅ = √15/15. What is the value of cos∅?

Ket [755]

Cos (theta) would be equal to 15/-1!

The reason is because the inverse of sin is equal to the hypotenuse over the opposite angle, meaning the hypotenuse would be -1. Tan is equal to the opposite over the adjacent angle, meaning the adjacent angle equals 15. Cos is equal to the adjacent over the hypotenuse, making cos (theta)= 15/-1!

4 0

3 years ago

What is the volume of the container below? 10 in. 4 in. 20 in. 6 in. 14 in.

weeeeeb [17]

Its 1,680 bc volume is l*w*h

4 0

3 years ago

Read 2 more answers

If two people are randomly selected, what is the probability both are hopelessly romantichopelessly romantic? what is the prob

vova2212 [387]

I'm so sorry i dont know the answer

5 0

3 years ago

The CEO of the Jen and Benny's ice cream company is concerned about the net weight of ice cream in their 50 ounce ice cream tubs

MissTica

Answer:

$t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025$

We need to find the degrees of freedom given by:

$df = n-1= 26-1 = 25$

Since is a right tailed test the p value would be:

$p_v =P(t_{25}>1.8025)=0.0418$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=54.98$ represent the sample mean

$s=8.43$ represent the sample deviation

$n=26$ sample size

$\mu_o =52$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 52, the system of hypothesis would be:

Null hypothesis: $\mu \leq 52$

Alternative hypothesis: $\mu > 52$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025$

P-value

We need to find the degrees of freedom given by:

$df = n-1= 26-1 = 25$

Since is a right tailed test the p value would be:

$p_v =P(t_{25}>1.8025)=0.0418$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.

7 0

3 years ago

Read 2 more answers

How would I graph this inequality? <img src="https://tex.z-dn.net/?f=7x%2B3y%5C%20%20%5Ctextless%20%5C%206-5x" id="TexFormul

Anon25 [30]

Answer:

the graph in the attached figure

Step-by-step explanation:

we have

$7x+3y$