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3 years ago

14

Point R is located between points Q and S. Point R is located at (3, 2) and point S is located at (8, 15). If R is the midpoint,

what are the coordinates of point Q?

1 answer:

Lubov Fominskaja [6]3 years ago

7 0

Answer:

(5.5,8.5)

Step-by-step explanation:

(8+3)÷2=5.5

(15+2)÷2=8.5

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Hey guys, I have a test and Im dying to get over a 700% can yall help me out here ill give 10 points

MArishka [77]

Answer:

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3 years ago

Mai bought gas for her car. Gas cost $2.95 per gallon Mai bought 8.2 gallons What was the total cost for Mai's gas?

yulyashka [42]

Answer: $24.19

Step-by-step explanation:

From the question, we are informed that Mai bought gas for her car which cost $2.95 per gallon and that she bought 8.2 gallons.

The total cost for Mai's gas will be:

= $2.95 × 8.2

= $24.19

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3 years ago

a recent survey shows that 16% of college students have dogs and 38% have an HBO subscription. assuming these two events are ind

Nataly_w [17]

Answer: $0.939\ or\ 93.9\%$

Step-by-step explanation:

Given

Survey shows that 16% of college students have dogs and 38% have HBO subscription

Probability that a random person have both is

$\Rightarrow P_o=0.16\times 0.38\quad [\text{As both events are independent}]\\\Rightarrow P_o=0.0608$

The probability that the random person has neither of the two is

$\Rightarrow P=1-P_o\\\Rightarrow P=1-0.0608\\\Rightarrow P=0.939$

3 0

3 years ago

7% of what lenght is 200 ft?

Nastasia [14]

If you would like to solve 7% of what length is 200 ft, you can calculate this using the following steps:

7% of what length is 200 ft
7% * x = 200
7/100 * x = 200 /*100/7
x = 200 * 100 / 7
x = 2857 ft

Result: 7% of 2857 ft is 200 ft.

5 0

3 years ago

Read 2 more answers

If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)

sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

4 0

3 years ago