Lines <em>a</em> and <em>b</em> are parallel, so lines <em>p</em>, <em>q</em>, and <em>t</em> are considered to be transversals. To solve this, you make use of the fact that alternate interior angles are equal, as are alternate exterior angles, as are corresponding angles. Of course any linear pair of angles is supplementary.
∠1 = 90° — corresponding angle to the right angle above it
∠2 = 68° — the sum of 22° and angles 1 and 2 is 180°
∠3 = 112° — supplementary to angle 2 (and the sum of 22° and 90°, opposite interior angles of the triangle)
∠4 = 112° — equal to angle 3
∠5 = 68° — equal to angle 2; supplementary to angle 4
∠6 = 56° — base angle of isosceles triangle with 68° at the apex; the complement of half that apex angle
∠7 = 124° — supplementary to the other base angle, which is equal to angle 6; also the sum of angles 5 and 6
∠8 = 124° — alternate interior angle with angle 7, hence its equal.
Answer:
Option D.
Step-by-step explanation:
The given points are (-2,0), (0,1), (0,-4) and (3,0).
In each ordered pair first element is x-coordinate and second is y-coordinate.
For 4 points, the table must have 2 columns and 4 rows.
So, the required table of values is
x y
-2 0
0 -4
0 1
3 0
Therefore, the correct option is D.
Answer:
2317.2
Step-by-step explanation:
2327.2-10
=2317.2
The intercepts of the given equations is as given in the task content is; Choice B; (15,0,0),(0,10,0) ,(0,0,5).
<h3>What are the intercepts of the equation as give in the task content?</h3>
The x-intercept of the given equation can be determined by setting values of y and z to zero.
The y-intercept can be determined by setting x and z to zero.
While the z-intercept can be determined by setting x and y to zero.
Consequently, the X-intercept of the given equations is; 2x +3(0) = 30; x = 15.
Therefore, we have; (15,0,0)
The y-intercept is therefore; 2(0) +3y = 30; 3y = 30; y = 30/3 = 10 and. we have; (0,15,0)
And hence, the z-intercept is; z = 30/6 = 5.
Read more on intercept;
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