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Fudgin [204]
3 years ago
15

Consider the equation below

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0

Answer: B

Step-by-step explanation:

Let's solve the given equation. Then we can see which other equation has the same answer.

-5n+31=-14n-5

36=-9n

n=-4

We need to fina another equation that gives n=4 as the answer.

A. Incorrect

3-6n+3n=-3+4-4n

3-3n=1-4n

n=-2

B. Correct

\frac{11}{4} n+2=-3+\frac{3}{2}n

\frac{5}{4}n=-5

n=-4

C. Incorrect

1=0.75n+3.25

-2.25=0.75n

n=-3

D. Incorrect

-1-22n=-20n-9

8=2n

n=4

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Step-by-step explanation:

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Answer:

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Which step is the same in the construction of parallel lines and the construction of a perpendicular line through a point on the
madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

- Given line AB and point P lies on it

1. <u>Place your compass pin at P </u>and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

*<em> Lets find the same steps in the constructions</em>

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

6 0
3 years ago
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Since we are asked for tge graph that represent the total cost for the x numbers of lesson, it will be helpful to illustrate it first this way

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Answer:

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Step-by-step explanation:

2 dozen is 24 so if he used a dozen which is 12 then he would have 12 left

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