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lesya [120]
3 years ago
13

Francesca bought a rectangular piece of fabric that is 2/3 yard long and 3/4 yard wide. What is the area, in square yards, of th

e piece of fabric?
Mathematics
1 answer:
ollegr [7]3 years ago
6 0

Answer:

area \:  = length  \times width \\  =  \frac{2}{3} \times  \frac{3}{4}  \\  =  \frac{(2 \times 3)}{(3 \times 4)}   \\ =  \frac{6}{12}  \\ area =  \frac{1}{2} square \: yards

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Pls help asap adn dont guess :DD
sashaice [31]

Answer:

{ \huge \star} \boxed{ \sqrt{3} \times 7 \sqrt{6}}{ \huge \star}  \\  =  \sqrt{3}  \times 7 \times  \sqrt{2 \times 3}  \\ =  3 \times 7 \times  \sqrt{2}  \\ =  \boxed{ 21 \sqrt{2}}

<h3><u>21√2</u> is the right answer.</h3>
3 0
3 years ago
For the following pair of variables, state the units that might be used to measure each variable. Then state whether you believe
AfilCa [17]

Answer:

The correct answer is:

There is a positive correlation because women's weight tend to increase when height increases (D)

Step-by-step explanation:

The units that might be used to measure each variable are:

Height : meter (m) or foot (plural, feet) (Ft.)

weight : kilograms (kg) or Pounds (lb)

A positive correlation is said to occur between two variables when they both move in the same direction, that is, when they both increase or decrease, while a negative correlation occurs when the movement is not in tandem, i.e, as one increases, the other decreases. The relationship between height and weight is a positive correlation because, an increase in height, which is mainly as a result of elongation of bones, leads to an accumulated increase in total body mass, which in turn increases the body weight.

8 0
3 years ago
Use the given information to find the exact value of the trigonometric function
eimsori [14]
\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}

Half Angle Formula

\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\  \\  \end{gathered}

Answer:

\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}

Checking:

\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{  (3rd quadrant)} \end{gathered}

Also,

\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}

The answer is none of the choices

7 0
1 year ago
A club logo is made from a square and a trapezium.
Viktor [21]

Answer:

hi im from another country see ya ... your country is amazing

Step-by-step explanation:

4 0
3 years ago
a closed circular water tank in a subdivision is made up of concreate aluminum. its outer diameter is 8.4 m and its height is 12
m_a_m_a [10]

Answer:

122.7792 sq. m

Step-by-step explanation:

diameter= 8.4 m

therefore, radius = r = 4.2 m.......( as radius is 1/2 of diameter)

height = h= 12 m

only the exterior is to painted so the total surface area of the cylinder is taken,

total surface area of cylinder = 2π r( h+r)

=2* 3.14* 4.2*(12+4.2)

=122.7792 sq. m

5 0
3 years ago
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