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Aleks04 [339]
3 years ago
9

If 15 cans of food are needed for 7 men for 2 days, the number of cans for 4 men for 7 days is

Mathematics
2 answers:
KatRina [158]3 years ago
8 0
15/2 = 7.5 can per dat

7.5/7 = 1.1 = 1 can per man

1 x 4 = 4 cans per day

4 x 7 = 28

Final answer would be 28 if you round. If you don’t the answer would come out to be 30.8. Take your pick.
Scorpion4ik [409]3 years ago
6 0
If 15 cans of food are needed for 7 men for 2 days, then 30 cans of food are needed for 4 men for 7 days. 

Assuming that the men eat every day, without skipping a day, then the first part of the sentence is basically saying 15 cans can feed 14 men. There are seven men who can survive off part of the 15 cans on day one, and seven men who can survive off of what's left of the 15 cans on day two.  The 15 cans have the potential to feed 14 men in one day basically. Applying this same theory, x number of cans has the potential to feed 28 (that's 4 men for 7 days). If these cans are the same size and are equal in terms of how filling its contents are, then we can set up a proportion.

15/14 = x/28
If 15 cans of food can feed 14 men, then x cans of food can feed 28 men.
Cross Multiply
14x = 420
Divide both sides by 14
x = 30

30 cans of food can feed 4 men for 7 days. Hope this helps!
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Answer:

-14

Step-by-step explanation:

Range is the difference between the lowest and highest values.

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3 years ago
The following lines are ______ <br><br> 4x + 2y = 10 y = -2x + 15
zmey [24]

Answer:

Parallel

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

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2y = - 4x + 10 ( divide through by 2 )

y = - 2x + 5 ← in slope- intercept form

with slope m = - 2

and

y = - 2x + 15 ← is in slope- intercept form

with slope m = - 2

• parallel lines have equal slopes

then the 2 lines are parallel

4 0
1 year ago
Read 2 more answers
Find the general term of the sequence<br>c.1 { 10, 5, 0, -5, -10 }<br>c.2 { 1, 4, 9, 16, 25 }​
Ivan

Answer:

1. 15 - 5n where n>=1

2. n² where n>=1

Step-by-step explanation:

1. {10, 5, 0, -5, -10} is an Arithmetic Progression

nth term is a + (n - 1)d

where a = first term, n= nth term, d= common difference.

a = 10, d = -5 (5-10, 0-5, -5-0, -10-(-5))

Therefore, nth(General) term of the sequence:

= 10 + (n - 1)-5

= 10 + (-5n) + 5

= 10 + 5 - 5n

= 15 - 5n

Test:

if n = 1; 15 - 5(1) = 10

if n = 2; 15 - 5(2) = 5

if n = 3; 15 - 5(3) = 0 and so on.

2. {1, 4, 9, 16, 25}

The general term of the sequence is n²

Test:

if n = 1; 1² = 1

if n = 2; 2² = 4

if n = 3; 3² = 9 and so on.

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3 years ago
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Helga [31]

Answer:

2

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3 years ago
The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co
Alona [7]

Answer:

95% Confidence interval for the variance:

3.6511\leq \sigma^2\leq 34.5972

95% Confidence interval for the standard deviation:

1.9108\leq \sigma \leq 5.8819

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

s^2=2.89^2=8.3521

The confidence interval for the variance is:

\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128

Then, the confidence interval can be calculated as:

\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819

6 0
3 years ago
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