Answer:
Given: Quadrilateral P QR S is a rectangle.
To prove :PR= Q S
Construction : Join PR and Q S.
Proof: In Rectangle PQRS, and
→ taking two triangles PSR and Δ QRS
1. PS = Q R
2. ∠ PS R = ∠ Q RS [Each being 90°]
3. S R is common.
→ ΔP SR ≅ Δ Q RS → [Side-Angle-Side Congruency]
∴ PR =Q S [ corresponding part of congruent triangles ]
Hence proved.
Answer:
x=-5
Step-by-step explanation
The first box has eight x's and six 1's which means that it would be written as 8x+6
The second box has four x's and fourteen -1's which means that it would be written as 4x-14
You set them equal to one another
8x+6=4x-14
You subtract 4x from both sides
4x+6=-14
Subtract 6 on both sides
4x=-20
Divide 4 on both sides
x=-5
Hope it helps :))
Answer:
b= 0.9
Step-by-step explanation:
first you find angle B: 180-90-25=65
then you will do law of sine- sin A/a=sin B/b=sin C/c
sin(90)/1=sin 65/b
sin(90)*b=sin(65)*1
sin(90)*b=0.9
b=0.9/sin(90)
b= 0.9
The new slope would now be 2 so y=2x-3
