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yawa3891 [41]
3 years ago
6

Find the radius of a right cylinder with a volume of 350 cubic feet and a height of 4 feet. Round your answer to the nearest hun

dredth.
Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

Radius=\sqrt{27.87} feet

Step-by-step explanation:

Volume of a right cylinder= \pi *r^2*h

Volume= 350 feet^3

Height(h)=4 feet

As, \pi =\frac{22}{7}=3.14

           350=3.14*r^2*4\\\\350=12.56*r^2\\\\r^2=350/12.56\\\\r^2=27.87\\\\r=\sqrt{27.87}feet

Radius=\sqrt{27.87} feet

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worty [1.4K]
We know that , in a circle radius perpendicular to chord will bisect the chord. 
OM=18, so OQ=QM=18/2=9.
 Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
6 0
3 years ago
harry is 14 years old ,and larry is 7. how many times older is harry than larry? what is known and the unknown ​
allsm [11]

Answer:

Harry is 7 more years older then larry

Step-by-step explanation:

Harry is 7 more years older then larry because if you sutract 7-14 you get 7

3 0
3 years ago
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A filter filled with liquid is in the shape of a vertex-down cone with a height of 9 inches and a diameter of 6 inches at its op
Alina [70]

Answer: Level of the liquid dropping at 28.28 inch/second when the liquid is 2 inches deep.

Step-by-step explanation:

Since we have given that

Height = 9 inches

Diameter = 6 inches

Radius = 3 inches

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V=\dfrac{1}{3}\pi r^2h\\\\V=\dfrac{1}{3}\pi \dfrac{1}{9}h^2\times h\\\\V=\dfrac{1}{27}\pi h^3

By differentiating with respect to time t, we get that

\dfrac{dv}{dt}=\dfrac{1}{27}\pi \times 3\times h^2\dfrac{dh}{dt}=\dfrac{1}{9}\pi h^2\dfrac{dh}{dt}

Now,  the liquid drips out the bottom of the filter at the constant rate of 4 cubic inches per second, ie \dfrac{dv}{dt}=-4\ in^3

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7 0
3 years ago
What is the recursive rule for an=4n−1? a1=4;an=an−1−1 a1=3;an=an−1+4 a1=−1;an=an−1+4 a1=3;an=an−1−1
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----------------------------------------------------------------------------

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Take a picture of the graph
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