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marishachu [46]
2 years ago
7

write an expression that is equivalent to -24 - 52 .(this is my question: what do i do for the sentence above? And please show m

e how you got the answer step by step.
Mathematics
1 answer:
Blababa [14]2 years ago
6 0
I think that it is simply asking to rewrite. So this would simplify to -76. But the expression -52-24 is also -76
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yKpoI14uk [10]

Answer:

Step-by-step explanation:

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In an anthropology class there are 77 anthropology majors and 1414 non-anthropology majors. 55 students are randomly selected to
Nata [24]

Answer:

P = 0.9989

Step-by-step explanation:

In order to do this, I will use the following numbers to make the calculations easier. In this case, We'll say that we have 7 majors and 14 non majors anthopology to present a topic.

This means that in the class we have 21 students.

Now, we choose 5 of them, and we want to know the probability that 1 of them is non major.

First, we need to calculate the number of ways we can select the students in all cases, and then, the probability.

First, we'll use the combination formula, to calculate the number of ways we can select the 5 students out of the 21. We use combination, because it does not matter the order that the students are selected.

C = m! / n!(m - n)!

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With this expression we will calculate first, how many ways we can choose the 5 students out of 21:

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Now let's calculate the number of ways you can get the all 5 students are non majors:

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Now we need to know the number of ways we can get 4 non majors and 1 major:

C3 = C3' * C3''

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C3 = 1001 * 7 = 7,007 ways to get 4 non majors and 1 major

Now the way to get 3 non majors and 2 majors, we do the same thing we do to get 4 non majors and 1 major, but changing the numbers. Then the way to get 2 non majors and 3 majors, and finally 1 non major and 4 majors:

3 non majors and 2 majors:

C4 = C4' * C4'' = [14! / 3!(14 - 3)!] * [7! / 2!(7 - 2)!] = 7,644

2 non majors and 3 majors:

C5 = C5' * C5'' = [14! / 2!(14 - 2)!] * [7! / 3!(7 - 3)!] = 3,185

1 non major and 4 majors:

C6 = C6' * C6'' = [14! / 1!(14 - 1)!] * [7! / 4!(7 - 4)!] = 490

Finally to know the probability of getting 1 out of the 5 to be non major, we have to sum all the previous results, and divide them by the ways we can choose the 5 students (C1):

P = 2,002 + 7,007 + 7,644 + 3,185 + 490 / 20,349

P = 0.9989

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Answer:

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Step-by-step explanation:

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