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mezya [45]
3 years ago
8

Expand the binomial (2x+5)^5

Mathematics
1 answer:
Whitepunk [10]3 years ago
3 0
That would simplify to 32x^5+400x^4+200x^3+5000x^2+6250x+3125
You would do that because you have to write it repeatedly as (2x+5)(2x+5) and so on.
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Solve for x.<br>A. x =9<br>B. x = 3<br>C. x = 4<br>D. x = 27
meriva
Your formula for this is 9^{2} =x(24+x) and 81=24x+ x^{2}.  Get everything on one side of the equals sign, set it equal to 0 and factor.  When you do this you get (x-3)(x+27). The Zero Product Property rule tells us that either x-3 = 0 or x+27 = 0 and that x = 3 and -27.  The only thing in math that will NEVER be negative besides time is distance/length, therefore, x cannot be 27 and has to be 3.
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faust18 [17]

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Dmitry [639]

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