Answer:
Step-by-step explanation:
Answer=
Well first we got to convert yards and feet into inches.
21 feet=252 inches
11 yards=396 inches
Alright so now that we have the inches needed we must find the cost for both Emily and Andy’s needed wire.
Emily:
We know how much it would cost for 200 inches, which is 8$.
15 inches adds a .60$ increase, which means that 5 inches is equivalent to .20$. By adding that to .60$ we get .80$ or the amount it would cost for 20 inches. We now know how much it would cost for 40 inches, 1.60$.
8+1.60=9.60 or how much it costs for 240 inches.
If it costs .80$ for 20 inches that means it costs .40$ for 10 inches.
9.60+.40=10
To find how much it costs for 2 inches we divide .40 by 5 which is .08.
10+.08=10.08$
Emily will spend 10.08$ for her needed wire.
Andy:
We know how much it would cost for 300 inches, which is 12$.
We also know how much it costs for 20 inches, which is .80$. So we multiply that by 4 to get how much it would cost for 80 inches.
.80*4=3.20
We then add that to the cost of 300 inches.
12+3.20=15.20
We know how much it would cost for 10 inches, which is .40$.
So we add that to the amount it would cost for 380 inches.
15.20+.40=15.60
Finally we know how much it costs for 2 inches, which is .08$. So we multiply that by 3 to find how much it costs for 6 inches.
.08*3=.24
We then add that to how much it would cost for 390 inches.
15.60+.24=15.84$
Andy will spend 15.84$ for his needed wire.
The length and width that will maximize the area are 175 ft and 87.5 ft respectively
The largest area that can be enclosed is 15312.5 ft²
<h3>Area of a rectangle</h3>
where
l = length
w = width
The fencing is 350 ft it is use to enclose a rectangular plot with a river occupying one part.
Therefore,
perimeter = l + 2w
350 = l + 2w
l = 350 - 2w
area = (350 - 2w)w
(350 - 2w)w = 0
where
w = 0 or 175
average = 175/2 = 87.5
Hence, the max area is at w = 87.5 ft
Therefore,
l = 350 - 2(87.5) = 175 ft
length = 175 ft
width = 87.5 ft
Therefore,
area = 175 × 87.5 = 15312.5 ft²
Therefore, the largest area that can be enclosed is 15312.5 ft²
learn more on rectangle here: brainly.com/question/11630499