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lubasha [3.4K]
3 years ago
5

Question 2 (5 points)

Mathematics
1 answer:
puteri [66]3 years ago
3 0

Answer:

12.5

Step-by-step explanation:

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What is the midpoint of the line whose end points are (5,9) and (-3,7).
AysviL [449]
Midpoint= \frac{x_{2}+ x_{1}}{2} ,  \frac{y_{2}+ y_{1}}{2}
              = \frac{5+(-3)}{2} ,  \frac{9+7}{2}
              = 1, 8
5 0
3 years ago
Read 2 more answers
Given h(x) = -x + 5, find h(-5).
Murrr4er [49]

Answer:

10

Step-by-step explanation:

h(x) = -(-5) + 5

h(x) = 5 + 5

h(x) = 10

3 0
2 years ago
For the last showing of a movie, a theater sold full-price and discount tickets,the theater sold 130 full-price ticket for a tot
sveta [45]

Answer:

the cost of 1 full price ticket is $9.5

Step-by-step explanation:

For the last showing of a movie, a theater sold full-price and discount tickets,the theater sold 130 full-price ticket for a total of $1235 the total sales both types of tickets were $2395

Let x be the number of full price tickets and y be the number of discount tickets

the theater sold 130 full-price ticket for a total of $1235 the total sales

130 full price tickets sold for $1235

the cost of 1 full price ticket is

\frac{1235}{130}=9.5

the cost of 1 full price ticket is $9.5

4 0
3 years ago
What is the value of the expression 5ab - 2c, where a = 2, b = 3 and c=0?
Len [333]

Answer:

30

Step-by-step explanation:

5*2*3-2*0 ( when we multiply any number with zero then the result is also zero)

30-0

30

5 0
3 years ago
Solve the system.
svetoff [14.1K]

Answer:

(0, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y + 5x = 1

5y - x = 5

<u>Step 2: Rewrite Systems</u>

y + 5x = 1

  1. Subtract 5x on both sides:                    y = 1 - 5x

<u>Step 3: Redefine Systems</u>

y = 1 - 5x

5y - x = 5

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitution in <em>y</em>:                      5(1 - 5x) - x = 5
  2. Distribute 5:                             5 - 25x - x = 5
  3. Combine like terms:                5 - 26x = 5
  4. Isolate <em>x</em> term:                          -26x = 0
  5. Isolate <em>x</em>:                                   x = 0

<u>Step 5: Solve for </u><em><u>y</u></em>

  1. Define equation:                    5y - x = 5
  2. Substitute in <em>x</em>:                       5y - 0 = 5
  3. Subtract:                                 5y = 5
  4. Isolate <em>y</em>:                                 y = 1
8 0
2 years ago
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