Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
Answer:
3p^2q^3r^2√r
Step-by-step explanation:
3√p^4q^6r^5
= 3p^2q^3r^2√r
Hope that helps
Answer:
The correct answer would be vertical angles
Step-by-step explanation:
The answer is vertical angles because the two lines make an acute angles that are equal to each other on both sides. I hope this helped!!! Have a good day!!!
