Someone's quiz grades in the second quarter. (78, 90, 95, 84, 80, 82, 87, 98, 72 ) Find the Median.
2 answers:
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Answer:
The first term indicates that the 14 student council members each handed out 22 flyers per additional minute of the fair. The second term indicates that the 14 members each handed out 25 flyers during the first minute of the fair.
Step-by-step explanation:
Given : The expression below represents the number of flyers handed out at the school fair by 14 members of the student council, where x is the number of minutes after the first minute of the fair. Assume that each student council member handed out the same number of flyers throughout the fair.
Expression : 14(22x) + 350
To Find: Interpret the meaning of each term in the expression.
Solution:
14 denotes the number of members
x is the number of minutes after the first minute of the fair
22 denotes each handed out 22 flyers per additional minute of the fair.
denotes each handed out 25 flyers during the first minute of the fair.
So, option A is true .
The first term indicates that the 14 student council members each handed out 22 flyers per additional minute of the fair. The second term indicates that the 14 members each handed out 25 flyers during the first minute of the fair.
Answer:
Step-by-step explanation:
Given the following question:
In order to multiply the two, we have to convert the mixed number into a improper fraction and then multiply the numerator by the numerator, the denominator by the denominator.
<u>Convert the improper fraction into a mixed number:</u>
Your answer is "1 1/9."
Hope this helps.
Answer:
750 < p < 1500
Step-by-step explanation:
The total cost of the affair for p attendees is ...
750 +2.25p
The average cost is that number divided by p. The answer choices suggest that "between" means that the cost per person cannot be 2.75 or 3.25. Applying the limits to the average cost, we get ...
2.75 < (750 +2.25p)/p < 3.25
2.75 < 750/p + 2.25 < 3.25 . . . . . . . . separating the fraction parts
0.50 < 750/p < 1.00 . . . . . . . . . . . . . . subtract 2.25
2 > p/750 > 1 . . . . . . . . . . . . . . . . . . . . . take the reciprocal*
1500 > p > 750 . . . . . . . . matches choice 4
_____
* Taking the reciprocals of numbers with the same sign reverses their order:
2 < 3 but 1/2 > 1/3
__
An alternate approach to the solution would be to multiply by p:
0.50p < 750 < 1.00p
To solve this requires it be made into two inequalities:
0.50p < 750 ⇒ p < 1500
and
750 < 1.00p ⇒ 750 < p
Then these would need to be recombined to form the answer:
750 < p < 1500
